Work Energy and Power - NEET Physics Questions
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Work Energy and Power

Question 61: easy

Water falls from a height of \(60\text{ m}\) at the rate of \(15\text{ kg/s}\) to operate a turbine. The losses due to frictional force are \(10%\) of the input energy. How much power is generated by the turbine? (\(g = 10\text{ m/s}^2\))

1. 7.0 kW
2. 10.2 kW
3. 8.1 kW
4. 12.3 kW
View Answer

The total input power is \(P_{\text{in}} = \frac{dm}{dt} gh = 15 \times 10 \times 60 = 9000\text{ W} = 9\text{ kW}\). Given that \(10%\) of energy is lost to friction, the efficiency is \(90%\), so the power generated is \(P_{\text{out}} = 0.9 \times 9\text{ kW} = 8.1\text{ kW}\).

Question 62: moderate

A body of mass 1 kg travels in a straight line with velocity \(v = \alpha x^{3/2}\) where \(\alpha = 10\text{ m}^{-1/2}\text{ s}^{-1}\). The work done by the net force during its displacement from \(x = 1\text{ m}\) to \(x = 3\text{ m}\) is

1. 50 J
2. 100 J
3. 1300 J
4. 500 J
View Answer

According to the work-energy theorem, \(W = \Delta K = \frac{1}{2}m(v_f^2 - v_i^2)\). Substituting \(v_i = 10\text{ m/s}\) and \(v_f = 30\sqrt{3}\text{ m/s}\), we obtain \(W = \frac{1}{2} \times 1 \times (2700 - 100) = 1300\text{ J}\).

Question 63: easy

A body of mass 10 kg moves along a smooth inclined plane \( \theta = 30^\circ\) with constant velocity through a distance of 10 m. Calculate the work done by applied external force to move the body through desired distance of 10 m.

1. 100 J
2. 150 J
3. 500 J
4. 400 J
View Answer

Since velocity is constant, the external force must balance gravity along the incline: \(F = mg sin theta\). The work done is \(W = F \cdot d = 10 \times 10 \times sin(30^\circ) \times 10 = 500\text{ J}\).

Question 64: easy

A particle of mass 4 kg is performing S.H.M. in a straight line under the action of force \( F = (15 – 3x) \text{ N} \). Equilibrium position of particle will be

1. x = 3 m
2. x = 5 m
3. x = 7 m
4. x = 10 m
View Answer

At the equilibrium position of a simple harmonic oscillator, the net restoring force acting on the particle is zero. Setting \( F = 15 - 3x = 0 \) yields \( 3x = 15 ⇒ x = 5 \text{ m} \).

Question 65: easy

Two masses \(1\text{ g}\) and \(9\text{ g}\) are moving with equal kinetic energies. The ratio of the magnitudes of their respective linear momenta is

1. \(1 : 9\)
2. \(9 : 1\)
3. \(1 : 3\)
4. \(3 : 1\)
View Answer

Since linear momentum \(p = \sqrt{2mK}\) and kinetic energy \(K\) is constant, \(p \propto \sqrt{m}\). Therefore, the ratio of momenta is \(\frac{p_1}{p_2} = \sqrt{\frac{1}{9}} = 1:3\).

Question 66: easy

When a spring is stretched by 1 cm, it stores energy 50 J. If it is further stretched by 1 cm, the stored energy will be

1. 50 J
2. 100 J
3. 150 J
4. 200 J
View Answer

The energy stored in a spring is \(U = \frac{1}{2}kx^2\). If stretched by 1 cm, \(U_1 = 50\text{ J}\). If further stretched by 1 cm, total stretch becomes 2 cm, so the stored energy is \(U_2 = \frac{1}{2}k(2x)^2 = 4U_1 = 200\text{ J}\).

Question 67: easy

Assertion (A): The work done during a round trip is always zero.


Reason (R): No force is required to move a body in its round trip.

1. Both (A) & (R) are true and the (R) is the correct explanation of the (A)
2. Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
3. (A) is true but (R) is false
4. Both (A) and (R) are false
View Answer

Work done by conservative forces in a closed loop is zero. For all forces, it depends on energy change and non-conservative forces. Force is required to move a body, especially to overcome inertia or friction. Therefore, both Assertion (A) and Reason (R) are false.

Question 68: easy

Assertion (A): Work done by conservative force along closed path is zero.


Reason (R): When an object is moved along closed path beginning and ending are at same point its displacement is zero.

1. Both (A) & (R) are true and the (R) is the correct explanation of the (A)
2. Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
3. (A) is true but (R) is false
4. Both (A) and (R) are false
View Answer

Assertion is true by definition of a conservative force, which does zero work over any closed path.


Reason is also true as displacement is zero for a closed path, i.e., \(\Delta \vec{r} = 0\). However, the reason is not the correct explanation for why work by a conservative force is zero; this is due to path independence and \(\Delta U = 0\) for a closed path.


Thus, both are true, but R is not the correct explanation of A.

Question 69: easy

Assertion (A): When a non-conservative force is involved in a system, it may dissipate energy.


Reason (R): The work done by a non-conservative force is always negative.

1. Both (A) & (R) are true and the (R) is the correct explanation of the (A)
2. Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
3. (A) is true but (R) is false
4. Both (A) and (R) are false
View Answer

Assertion is true: Non-conservative forces like friction or air resistance dissipate mechanical energy into other forms (e.g., heat).


Reason is false: The work done by a non-conservative force is not always negative. For example, an applied external force can be non-conservative and do positive work on a system.


Thus, A is true but R is false.

Question 70: easy

Assertion (A): The sum of potential and kinetic energy for a system of moving objects is conserved only when no net external force acts on the objects


Reason (R): If no nonconservative force acts on a system of objects, the work done by external forces on a system of objects is equal to change in potential energy plus change in kinetic energy of the system.

1. Both (A) & (R) are true and the (R) is the correct explanation of the (A)
2. Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
3. (A) is true but (R) is false
4. Both (A) and (R) are false
View Answer

Assertion is false: Mechanical energy \(E = K + U\) is conserved when only conservative forces do work. External conservative forces (e.g., gravity) can act and do work, yet mechanical energy can be conserved.


Reason is false: If no non-conservative forces act, then \(\Delta K + \Delta U = 0\), meaning mechanical energy is conserved. In this scenario, the work done by external forces \(W_{ext}\) is not necessarily zero. For instance, gravity does work when an object falls, but \(E\) is conserved.


Therefore, both Assertion and Reason are false.