Solution:
Since velocity is constant, the external force must balance gravity along the incline: \(F = mg sin theta\). The work done is \(W = F \cdot d = 10 \times 10 \times sin(30^\circ) \times 10 = 500\text{ J}\).
A body of mass 10 kg moves along a smooth inclined plane \( \theta = 30^\circ\) with constant velocity through a distance of 10 m. Calculate the work done by applied external force to move the body through desired distance of 10 m.
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