Current Electricity - NEET Physics Questions
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Current Electricity

Question 21: easy

The drift velocity of free electrons in a conductor is \(v\) when a current \(i\) is flowing in it. If both the area of cross-section and current are doubled, then drift velocity will be

1. 2v
2. \[\frac{v}{2}\]
3. v
4. 4v
View Answer

Formula: \(v_d = \frac{i}{n A e}\). If both \(i\) and \(A\) are doubled, the drift velocity \(v_d\) remains unchanged as the ratio \(\frac{i}{A}\) is constant.

Question 22: easy

Two batteries one of emf \(18\text{ V}\) and internal resistance \(3\text{ }\Omega\) while other of emf \(12\text{ V}\) and internal resistance \(2\text{ }\Omega\) are connected in parallel with positive terminals together at one point and negative terminals together to other point. If across these points an ideal voltmeter is connected, the reading of voltmeter will be

1. 16 V
2. 14.4 V
3. 15.3 V
4. 12.6 V
View Answer

The potential difference is the equivalent EMF: \(E_{\text{eq}} = \frac{E_1/r_1 + E_2/r_2}{1/r_1 + 1/r_2} = \frac{18/3 + 12/2}{1/3 + 1/2} = \frac{12}{5/6} = 14.4\text{ V}\).

Question 23: easy

Pick out wrong statement about the Kirchhoff’s laws of electric circuit.

1. Outgoing currents adds up and are equal to incoming currents at a junction
2. Starting with any point if we come back to same point, total potential change must be zero
3. Junction rule is based on conservation of energy law
4. Bending or reorienting the wire does not change the validity of Kirchhoff’s junction rule.
View Answer

Kirchhoff's first law (the junction rule) is based on the law of conservation of charge, not energy. The second law (loop rule) is based on the conservation of energy.

Question 24: easy

A \((100 \text{ W}, 200 \text{ V})\) bulb is connected to a \(160 \text{ V}\) supply. The power consumed by the bulb will be

1. 100 W
2. 125 W
3. 64 W
4. 80 W
View Answer

The resistance of the bulb is given by \(R = \frac{V^2}{P} = \frac{200^2}{100} = 400 \, \Omega\). When connected to a \(160 \text{ V}\) supply, the power consumed is \(P' = \frac{V'^2}{R} = \frac{160^2}{400} = 64 \text{ W}\).

Question 25: easy

A wire of a certain material is stretched slowly by 10%. Its new resistance and specific resistance will respectively become

1. 1.2 times, 1.1 times
2. 1.1 times, 1.1 times
3. Same, same
4. 1.21 times, same
View Answer

Specific resistance (resistivity) depends only on the material and temperature, so it remains same. Resistance \(R \propto l^2\) when a wire is stretched. If length is increased by 10% (\(l' = 1.1l\)), the new resistance is \(R' = (1.1)^2 R = 1.21 R\).

Question 26: easy

A wire of resistance \(12\text{ }\Omega\) is bent to form a circle. The equivalent resistance between two diametrically opposite points will be

1. \(3\text{ }\Omega\)
2. \(6\text{ }\Omega\)
3. \(12\text{ }\Omega\)
4. \(18\text{ }\Omega\)
View Answer

Bending the wire into a circle divides it into two halves of equal resistance \(6\text{ }\Omega\) in parallel between diametrically opposite points. The equivalent resistance is \(R_{\text{eq}} = \frac{6 \times 6}{6 + 6} = 3\text{ }\Omega\).

Question 27: easy

Consider the following statements and choose the correct option


Statement (A): Electromotive force (emf) is not a force, it is the voltage difference between two terminal of a battery in open circuit.


Statement (B): The potential difference across terminals of a battery having some internal resistance can never be greater than the emf of the battery.


 

1. Statement (A) is correct while statement (B) is incorrect
2. Statement (A) is incorrect while statement (B) is correct
3. Both the statements are correct
4. Both the statements are incorrect
View Answer

Statement (A) is correct as EMF is indeed a potential difference under open circuit. Statement (B) is incorrect because during charging, the terminal potential difference is \(V = E + Ir\), which is greater than the EMF \(E\).

Question 28: easy

The energy used by a 100 W bulb which is on for 10 hours is:

1. 1 kWh
2. \( 3.6 \times 10^6 \, \text{J} \)
3. \( 4.8 \times 10^5 \, \text{J} \)
4. Both (1) and (2)
View Answer

Energy is calculated as \( E = P \times t = 100 \, \text{W} \times 10 \, \text{h} = 1000 \, \text{Wh} = 1 \, \text{kWh} \). In standard SI units, this is \( 1000 \, \text{W} \times 3600 \, \text{s} = 3.6 \times 10^6 \, \text{J} \). Thus, both Options (1) and (2) are correct.

Question 29: easy

Assertion (A): When constant current is passing through a conductor of variable area of cross section, electric field inside conductor is inversely proportional to cross sectional area.


Reason (R): Microscopic form of Ohm’s law is \( \vec{E} = \rho \vec{J} \), where \( \vec{E} \) stands for electric field, \( \rho \) stands for resistivity and \( \vec{J} \) stands for current density.


 

1. (1) Both (A) & (R) are true and the (R) is the correct explanation of the (A)
2. (2) Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
3. (3) (A) is true but (R) is false
4. (4) Both (A) and (R) are false
View Answer

Assertion (A) is true because \( I = JA \) and \( E = \rho J \) imply \( E = \frac{\rho I}{A} \). Reason (R) is true as it's the microscopic form of Ohm's law. Reason correctly explains assertion.

Question 30: easy

Assertion (A): The current density \( \vec{J} \) at any point in ohmic resistor is in direction of electric field \( \vec{E} \) at that point.


Reason (R): A point charge when released from rest in a region having only electrostatic field always moves along electric lines of force.


 

1. (1) Both (A) & (R) are true and the (R) is the correct explanation of the (A)
2. (2) Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
3. (3) (A) is true but (R) is false
4. (4) Both (A) and (R) are false
View Answer

Assertion (A) is true from \( \vec{J} = \sigma \vec{E} \) where \( \sigma \) is conductivity. Reason (R) is false because a charge released from rest moves along an electric field line only if the field line is straight, which is not always true.