Current Electricity - NEET Physics Questions
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Current Electricity

Question 11: moderate

An ammeter and a voltmeter are joined in series to a cell. Their readings are A and V respectively. If a resistance is now joined in parallel with the voltmeter

1. both A and V will increase
2. both A and V will decrease
3. A will decrease, V will increase
4. A will increase, V will decrease
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Initial Setup:

  1. An ammeter and a voltmeter are connected in series to a cell.
  2. The ammeter reading is
    AA
     

    (current through the circuit).

  3. The voltmeter reading is
    VV
     

    (potential difference across the cell).


What Happens When a Resistance is Added in Parallel with the Voltmeter?

  • The voltmeter has a high internal resistance (
    RvR_v
     

    ) to minimize current flow through it.

  • When an additional resistance (
    RR
     

    ) is connected in parallel with the voltmeter, the effective resistance of the voltmeter decreases because: Reff=RvRRv+R.R_{\text{eff}} = \frac{R_v \cdot R}{R_v + R}. 

    Since RR 

    is finite, Reff<RvR_{\text{eff}} < R_v 

    .


Effect on the Circuit:

  1. Decrease in total resistance:
    • The voltmeter (and its parallel combination) is in series with the ammeter.
    • The decrease in
      ReffR_{\text{eff}}
       

      reduces the total resistance of the circuit.

    • Lower resistance means higher total current through the circuit (Ohm's law:
      I=VRtotalI = \frac{V}{R_{\text{total}}}
       

      ).

    • Thus, the ammeter reading (
      AA
       

      ) increases.

  2. Voltage across the voltmeter decreases:
    • With the reduced effective resistance of the voltmeter, a smaller fraction of the total voltage is dropped across it.
    • Hence, the voltmeter reading (
      VV
       

      ) decreases.


Conclusion:

When a resistance is added in parallel with the voltmeter:

  • The ammeter reading (
    AA
     

    ) increases.

  • The voltmeter reading (
    VV
     

    ) decreases.

Question 12: moderate

In the following circuit diagram, the current flowing through resistor of 1/4Ω is :

1. 1 A
2. 60 A
3. 30 A
4. None of these
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Question 13: moderate

In the given circuit the current flowing through the resistance 20 ohms is 0.3 ampere while the ammeter reads 0.8 ampere. What is the value of R1?

1. 30 ohms
2. 40 ohms
3. 60 ohms
4. 50 ohms
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Question 14: moderate

A battery of emf E is connected across a conductor as shown. As one observes from A to B.

Now, match the given columns and select the correct option from the codes given below :
Codes :

1. I-p, II-q, III-r, IV-s
2. I-r, II-q, III-q, IV-q
3. I-q, II-p, III-s, IV-r
4. I-s, II-q, III-q, IV-p
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Question 15: difficult

In the given figure if r = 2 Ω then the current flown through the battery is –

1. 3A
2. 4A
3. 5/2 A
4. 3/2 A
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Question 16: moderate

The resistance of the ammeter shown in figure is 0.8 Ω . Its reading is

1. zero
2. 0.6 A
3. 1.2 A
4. none of these
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Question 17: moderate

Six resistors each of 10 W are connected as shown. The equivalent resistance between points X and Y is :

1. 20 Ω
2. 5 Ω
3. 25/3 Ω
4. 10 Ω
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Question 18: difficult

In the given network, the equivalent resistance between A and B is:

1. 6 Ω
2. 16 Ω
3. 7 Ω
4. 5 Ω
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Question 19: difficult

What is the current in branch AB of the circuit shown?

1. 1.5 A
2. 2 A
3. 1.33 A
4. Infinite
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Question 20: moderate

A and B are two points on a uniform ring of resistance R. The ∠ACB = θ, where C is the centre of the ring. The equivalent resistance between A and B is

1. \[R\frac{2\pi-\theta}{4\pi}\]
2. \[R\left( 1-\frac{\theta}{2\pi} \right)\]
3. \[R\frac{\theta}{2\pi}\]
4. \[\frac{R}{4\pi^{2}}\left( 2\pi-\theta \right)\theta\]
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