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Growth of Current in an Inductor

Practice Questions:

Question 1: easy

The adjoining figure shows two bulbs B1 and B2 resistor R and an inductor L. When the switch S is turned off :

1. Both B1 and B2 die out promptly

2. Both B1 and B2 die out with some delay

3. B1 dies out promptly but B2 with some delay

4. B2 dies out promptly but B1 with some delay

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Question 2: easy

The expression for magnetic induction inside a solenoid of length \(L\) carrying a current \(I\) and having \(N\) number of turns is:

1. \(\frac{\mu_0 N}{4\pi L I}\)

2. \(\mu_0 N I\)

3. \(\frac{\mu_0}{4\pi} N L I\)

4. \(\mu_0 \frac{N}{L} I\)

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Magnetic field inside a long solenoid is given by \(B = \mu_0 n I\), where \(n = \frac{N}{L}\) is the number of turns per unit length. Therefore, \(B = \mu_0 \frac{N}{L} I\).

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