An inductor L, a resistance R and two identical bulbs, B1 and B2 are connected to a battery
through a switch S as shown in the figure. Which of the following statements gives the correct
description of the happenings when the switch S is closed ?
The adjoining figure shows two bulbs B1 and B2 resistor R and an inductor L. When the switch S is turned off :
Two resistors of 10 W and 20 W and an ideal inductor of 10 H are connected to a 2 V battery
as shown. The key K is inserted at time t = 0. The initial (t = 0) and final (t →∞) currents
through battery are
The network shown in the figure is part of a complete circuit. If at a certain instant, the current
I is 5A and it is decreasing at a rate of
\[10^{3} As^{-1} then V_{B}-A_{A} equals\]
For the circuit shown in figure R = 10Ω, L = 5H, E = 20 V, i = 2 A. This current is decreasing at
a rate of 1.0 A /s Find Vab at this instant.
The figure shows three circuits with identical batteries, inductors, and resistors. Rank the circuits according to the current through the battery (i) just after the switch is closed and (ii) a long time later, greatest first :
(i) Just after the switch is closed (t = 0): An inductor opposes any sudden change in current. Initially, it acts like an infinite resistance (open circuit). No current can flow through any branch containing the inductor at this instant.
(ii) A long time later (t =infinity): Once the current reaches a steady state, the inductor no longer opposes the flow. It acts like an ideal wire (short circuit) with zero resistance. You can then rank the circuits by calculating the total equivalent resistance of the remaining resistors.
An ideal coil of 10H is connected in series with a resistance of 5Ω and a battery of 5V. 2 seconds after the connection is made, the current flowing in amperes in the circuit is :
The expression for magnetic induction inside a solenoid of length \(L\) carrying a current \(I\) and having \(N\) number of turns is:
Magnetic field inside a long solenoid is given by \(B = \mu_0 n I\), where \(n = \frac{N}{L}\) is the number of turns per unit length. Therefore, \(B = \mu_0 \frac{N}{L} I\).