Magnetic Induction inside Solenoid – Rankers Physics
Topic: Electromagnetic Induction
Subtopic: Growth of Current in an Inductor

Magnetic Induction inside Solenoid

The expression for magnetic induction inside a solenoid of length \(L\) carrying a current \(I\) and having \(N\) number of turns is:
\(\frac{\mu_0 N}{4\pi L I}\)
\(\mu_0 N I\)
\(\frac{\mu_0}{4\pi} N L I\)
\(\mu_0 \frac{N}{L} I\)

Solution:

Magnetic field inside a long solenoid is given by \(B = \mu_0 n I\), where \(n = \frac{N}{L}\) is the number of turns per unit length. Therefore, \(B = \mu_0 \frac{N}{L} I\).

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