Thermal Physics - NEET Physics Questions
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Thermal Physics

Question 221: easy

A blackbody and a real body of identical dimensions are heated to same temperature. If ratio of rates of radiation of the blackbody and the real body is $4 : 3$, then emissivity of the real body is equal to

1. 0.25
2. 0.50
3. 0.75
4. 0.67
View Answer

The rate of radiation is given by $E = e\sigma A T^4$. For a blackbody, $e = 1$. Given $\frac{E_b}{E} = \frac{4}{3} ⇒ \frac{1}{e} = \frac{4}{3}$, hence emissivity $e = 0.75$.

Question 222: easy

Water equivalent of a metallic bar is $100\text{ g}$, the energy required to increase its temperature by $1^\circ\text{C}$ is

1. 100 cal
2. 1000 cal
3. 500 cal
4. 50 cal
View Answer

Energy required is $Q = w \cdot \Delta T$, where $w$ is the water equivalent. Thus, $Q = 100\text{ g} \times 1\text{ cal/g}^\circ\text{C} \times 1^\circ\text{C} = 100\text{ cal}$.

Question 223: easy

For $n$ mole of an ideal gas, the correct equation of $1^{\text{st}}$ law of thermodynamics corresponding to isobaric process will be (symbols have their usual meanings)

1. $Q = \Delta U + P\Delta V$
2. $Q = \Delta U + nR\Delta T$
3. $Q = \Delta U$
4. Both (1) and (2)
View Answer

By first law, $Q = \Delta U + W$. In an isobaric process, the work done is $W = P\Delta V = nR\Delta T$. Therefore, both expressions are correct.

Question 224: easy

Consider the following thermodynamic parameters:
(a) Heat
(b) Internal energy
(c) Work

Which of the given parameters are path functions?

1. Only (a)
2. Both (a) and (b)
3. Both (b) and (c)
4. Both (a) and (c)
View Answer

Heat and work depend on the path taken between states, whereas internal energy is a state function. Therefore, (a) and (c) are path functions.

Question 225: easy

In ideal condition, the maximum efficiency that can be derived from a heat engine operating between $600\text{ K}$ reservoir and $200\text{ K}$ sink, is

1. 100%
2. 66.67%
3. 99.93%
4. 73.3%
View Answer

Efficiency is given by $\eta = 1 - \frac{T_{\text{sink}}}{T_{\text{source}}}$. Substituting the given values: $\eta = 1 -\frac{200}{600} =\frac{2}{3} \approx 66.67%$.

Question 226: easy

Which of the following is not the correct assumption of kinetic theory of gases?

1. No intermolecular force acts between gas molecules.
2. The volume of molecules is negligible in comparison to the volume of gas.
3. Molecules only collide with the walls of container, there is no collision among the molecules.
4. All collisions are elastic.
View Answer

Kinetic theory assumes that gas molecules undergo continuous random motion and collide with each other as well as with the walls of the container.

Question 227: easy

The equation of state for \(14\text{ g}\) nitrogen gas at a pressure \(P\) and temperature \(T\), when occupying a volume \(V\) will be

1. \(PV = 14RT\)
2. \(PV = \frac{1}{2}RT\)
3. \(PV = RT\)
4. \(PV = 2RT\)
View Answer

The molecular mass of nitrogen gas \((\text{N}_2)\) is \(28\text{ g/mol}\). The number of moles is \(n = \frac{14}{28} = 0.5\). Thus, using \(PV = nRT\), we get \(PV = \frac{1}{2}RT\).

Question 228: easy

The unit of emissive power is

1. \(\text{J m}^{-2}\)
2. \(\text{W s}^{-1}\)
3. \(\text{J m}^{-2}\text{ s}^{-1}\)
4. \(\text{W m}^2\text{ s}^{-1}\)
View Answer

Emissive power is defined as the thermal energy emitted per unit area per unit time, so its unit is \(\text{J m}^{-2}\text{ s}^{-1}\) (or \(\text{W m}^{-2}\)).

Question 229: easy

Two rods one made of material A and other made of material B of same length and same cross-sectional area are joined together. If thermal conductivity of material A is \(K_1\) while that of material B is \(K_2\) and the free end of rod made of material A is maintained at \(T_1\) while that of the rod of material B is maintained at \(T_2\), then the temperature of junction is (Where \(T_1 > T_2\))

1. \(\frac{T_1 + T_2}{2}\)
2. \(\frac{T_1 K_1 + T_2 K_2}{K_1 + K_2}\)
3. \(\frac{T_1 K_1 - T_2 K_2}{K_1 + K_2}\)
4. \(\frac{T_1 K_1 + T_2 K_2}{K_1 - K_2}\)
View Answer

Under steady state, the rate of heat flow is the same through both rods: \(\frac{K_1 A(T_1 - T_j)}{L} = \frac{K_2 A(T_j - T_2)}{L}\). Solving for \(T_j\) gives \(T_j = \frac{K_1 T_1 + K_2 T_2}{K_1 + K_2}\).

Question 230: easy

Consider the following statements out of which one is labelled as assertion and other as reason.


Assertion: The internal energy of an ideal monoatomic gas enclosed in a container does not change when there is no change in temperature.


Reason: Internal energy of a gaseous system is path function.


 

1. Both Assertion (A) and Reason (R) are true and Reason (R) is a correct explanation of Assertion (A).
2. Both Assertion (A) and Reason (R) are true but Reason (R) is not a correct explanation of Assertion (A).
3. Assertion (A) is true and Reason (R) is false.
4. Assertion (A) is false and Reason (R) is true.
View Answer

Internal energy of an ideal gas depends only on its temperature, so the Assertion is true. However, internal energy is a state function, not a path function, so the Reason is false.