If \(M\) is the molar mass of a gas, then the average speed of its molecules at temperature \(T\) is
1. \(\sqrt{\frac{3RT}{\pi M}}\)
2. \(\sqrt{\frac{8RT}{\pi M}}\)
3. \(\sqrt{\frac{2RT}{M}}\)
4. \(\sqrt{\frac{3RT}{M}}\)
View Answer
According to Maxwell-Boltzmann distribution, the average speed of molecules of an ideal gas is given by the expression \(v_{\text{avg}} = \sqrt{\frac{8RT}{\pi M}}\).
If transmittance of a surface is \(\frac{1}{7}\), reflectance is \(\frac{1}{8}\), then the absorptance of the surface will be
1. \(\frac{1}{9}\)
2. \(\frac{15}{56}\)
3. \(\frac{9}{56}\)
4. \(\frac{41}{56}\)
View Answer
By conservation of energy, the sum of absorptance \(a\), reflectance \(r\), and transmittance \(t\) is equal to \(1\): \(a + r + t = 1\). Therefore, \(a = 1 - \frac{1}{8} - \frac{1}{7} = 1 - \frac{15}{56} = \frac{41}{56}\).
Statement I: Internal energy of an ideal gas remains constant in an adiabatic process.
Statement II: In an adiabatic process, change in internal energy of a gas is equal to work done on or by the gas in the process.
1. Statement I is correct and statement II is incorrect
2. Statement I is incorrect and statement II is correct
3. Both statements are correct
4. Both statements are incorrect
View Answer
In an adiabatic process, \(Q = 0\), so \(\Delta U = -W\), which means internal energy changes, so Statement I is incorrect. Statement II is correct since change in internal energy corresponds directly to the work done on or by the gas.
A faulty thermometer shows $40^\circ\text{C}$ at ice point and $80^\circ\text{C}$ at steam point. The temperature at which its reading would be correct is
1. $\frac{100}{3} ^\circ\text{C}$
2. $\frac{200}{3} ^\circ\text{C}$
3. $60^\circ\text{C}$
4. $75^\circ\text{C}$
View Answer
Using the relation $\frac{T - \text{LFP}}{\text{UFP} - \text{LFP}} = \frac{C - 0}{100 - 0}$, we substitute $T = C$ for correct reading. This gives $\frac{C - 40}{80 - 40} = \frac{C}{100}$, which simplifies to $C = \frac{200}{3} ^\circ\text{C}$.