Refraction by Spherical Surfaces - NEET Physics Questions
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Refraction by Spherical Surfaces

Question 11: easy

Assertion (A): For better resolution, in microscope we prefer “Oil immersed object”.


Reason (R): Refractive index of oil is closer to the refractive index of objective glass.


 

1. (1) Both (A) & (R) are true and the (R) is the correct explanation of the (A)
2. (2) Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
3. (3) (A) is true but (R) is false
4. (4) Both (A) and (R) are false
View Answer

Oil immersion is used in microscopes to increase the numerical aperture (NA) and thus improve resolution. Thus, (A) is true.
The refractive index of the immersion oil is chosen to be very close to that of the objective lens glass, which minimizes refraction and maximizes the angle of light collected, increasing NA. Thus, (R) is true and is the correct explanation of (A).

Question 12: easy

Assertion (A): Rainbow is an example of the dispersion of sunlight by the water droplets.


Reason (R): Light of shorter wavelength is scattered much more than light of larger wavelength.


 

1. (1) Both (A) & (R) are true and the (R) is the correct explanation of the (A)
2. (2) Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
3. (3) (A) is true but (R) is false
4. (4) Both (A) and (R) are false
View Answer

Rainbows are formed due to dispersion and total internal reflection of sunlight by water droplets. Thus, (A) is true.
Rayleigh scattering states that the intensity of scattered light is inversely proportional to the fourth power of its wavelength \((I \propto 1/\lambda^4)), meaning shorter wavelengths (blue, violet) are scattered more than longer wavelengths (red). Thus, (R) is true.
However, (R) explains scattering, which is distinct from dispersion (dependence of refractive index on wavelength) responsible for the separation of colors in a rainbow. So, (R) does not explain (A).

Question 13: easy

Assertion (A): The persistence of vision \(1/16\) second is used in cinematography.


Reason (R): The human eye forms the real image of an object at its retina.


 

1. Both (A) & (R) are true and the (R) is the correct explanation of the (A)
2. Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
3. (A) is true but (R) is false
4. Both (A) and (R) are false
View Answer

Assertion (A) is true; the brain's retention of images for about \(1/16\) second creates motion from rapid stills. Reason (R) is true; the eye's lens system forms a real, inverted image on the retina. R describes a fundamental eye function, which is a prerequisite for A but not its direct explanation. Thus, both are true, but R does not explain A.

Question 14: easy

Assertion (A): A single lens cannot be free from chromatic aberration.


Reason (R): When light passes through single lens dispersion must occur.


 

1. Both (A) & (R) are true and the (R) is the correct explanation of the (A)
2. Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
3. (A) is true but (R) is false
4. Both (A) and (R) are false
View Answer

Chromatic aberration occurs because the refractive index of a lens material varies with wavelength (dispersion). A single lens always causes dispersion, leading to different focal points for different colors. Thus, both (A) and (R) are true, and (R) explains (A).

Question 15: easy

Assertion (A): If an object is placed between (f) and (2f) of a convex lens, a real image can be seen on a screen placed at image location. If the screen is removed then image will not be seen.


Reason (R): Real image of a object can not formed in air.


 

1. Both (A) & (R) are true and the (R) is the correct explanation of the (A)
2. Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
3. (A) is true but (R) is false
4. Both (A) and (R) are false
View Answer

A real image is formed by the actual intersection of light rays and exists in space independently of a screen. It can be viewed by the eye even without a screen. Real images are formed in the medium where rays converge, typically air. Therefore, both assertion and reason are false.

Question 16: easy

Assertion (A): For observing a rainbow, sun should be shining in one part of the sky and it is raining in the opposite part of sky, and observer should stand with his back towards raining side.


Reason (R): Rainbow appears due to directly reflection of sunlight from water drops of rain.


 

1. Both (A) & (R) are true and the (R) is the correct explanation of the (A)
2. Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
3. (A) is true but (R) is false
4. Both (A) and (R) are false
View Answer

For a rainbow, the sun must be behind the observer, and the rain in front. This means the observer's back should be towards the sun, not the raining side. Rainbow formation involves dispersion, total internal reflection, and refraction, not just direct reflection.

Question 17: easy

Assertion (A): Focal length of a convex mirror may be negative.


Reason (R): Distances measured in the direction of incident rays may be taken as negative.


 

1. Both (A) & (R) are true and the (R) is the correct explanation of the (A)
2. Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
3. (A) is true but (R) is false
4. Both (A) and (R) are false
View Answer

According to Cartesian sign convention, the focal length of a convex mirror is always positive as its principal focus is virtual and lies behind the mirror. Thus, (A) is false. While sign conventions involve directions, stating that distances measured in the direction of incident rays 'may be taken as negative' is generally incorrect or misleading; typically, these are taken as positive. Hence, (R) is also false. Thus, both (A) and (R) are false.

Question 18: moderate

Match the elements of List-I with List-II:

$$\begin{array}{ll} \textbf{List-I} & \textbf{List-II} \\ \hline \text{(A) Simple microscope} & \text{(H) Image virtual, erect and enlarged} \\ \text{(B) Compound microscope} & \text{(E) Image magnified, inverted and virtual} \\ \text{(C) Astronomical telescope} & \text{(G) Virtual, inverted and high resolution} \\ \text{(D) Terrestrial telescope} & \text{(F) Image virtual, erect and high resolution} \\ \end{array}$$
1. A-H, B-F, C-E, D-G
2. A-H, B-E, C-G, D-F
3. A-H, B-E, C-F, D-G
4. A-F, B-G, C-E, D-G
View Answer

A simple microscope forms an erect, virtual, and enlarged image (A-H). A compound microscope forms a magnified, inverted, and virtual final image (B-E). An astronomical telescope has a virtual, inverted, high resolution final image (C-G). A terrestrial telescope has a virtual, erect, high resolution final image (D-F).