Ray Optics - NEET Physics Questions
Question 91: easy

The refractive index of material of a plano-convex lens, if the radius of curvature of convex surface is 10 cm and focal length of lens is 30 cm is

1. μ = 2/3
2. μ = 1/3
3. μ = 4/3
4. μ = 1/2
View Answer

Using Lens Maker's formula for a plano-convex lens: \(\frac{1}{f} = (\mu - 1)\frac{1}{R} ⇒ \frac{1}{30} = (\mu - 1)\frac{1}{10} ⇒ \mu - 1 = \frac{1}{3} ⇒ \mu = \frac{4}{3}\).

Question 92: easy

Critical angle of light passing from water to air is maximum for

1. Yellow
2. Green
3. Blue
4. Indigo
View Answer

Critical angle is given by \(sintheta_c = frac{1}{mu}\). According to Cauchy's formula, the refractive index \(mu\) increases as wavelength decreases (Yellow > Green > Blue > Indigo in wavelength). Therefore, Yellow has the lowest refractive index and thus the maximum critical angle.

Question 93: easy

A ray of light is incident normally on one face of a thin prism of refractive index \(mu\) and emerges at an angle (e) from the normal. Angle of prism \(A\) is nearly

1. \(\frac{e}{mu}\)
2. \(\mu e\)
3. \(\frac{1-e}{\mu}\)
4. \(\mu\left(\frac{\pi}{2} - e\right)\)
View Answer

For normal incidence on the first face, the angle of refraction \(r_1 = 0\), which implies \(r_2 = A\). Applying Snell's law at the second face for small angles, \(e \approx \mu r_2 = \mu A\), giving \(A \approx \frac{e}{\mu}\).

Question 94: moderate

In the displacement method, a convex lens is placed in between an object and a screen. If magnification in the two positions are \(m_1\) and \(m_2\) (\(m_1 > m_2\)) and the distance between two positions of the lens is x, the focal length of the lens is

1. \(\frac{x}{m_1+m_2}\)
2. \(\frac{x}{m_1-m_2}\)
3. \(\frac{x}{(m_1+m_2)^2}\)
4. \(\frac{x}{(m_1-m_2)^2}\)
View Answer

In displacement method, \(m_1 = \frac{v_1}{u_1}\) and \(m_2 = \frac{v_2}{u_2} = \frac{u_1}{v_1}\). Since the distance between two positions is \(x = v_1 - u_1\), we obtain \(m_1 - m_2 = \frac{x}{f}\), hence \(f = \frac{x}{m_1-m_2}\).

Question 95: easy

The refractive index of material of a plano-convex lens, if the radius of curvature of convex surface is \(10\text{ cm}\) and focal length of lens is \(30\text{ cm}\) is

1. \(\mu = \frac{2}{3}\)
2. \(\mu = \frac{1}{3}\)
3. \(\mu = \frac{4}{3}\)
4. \(\mu = \frac{1}{2}\)
View Answer

Using lens maker's formula for a plano-convex lens, \(f = \frac{R}{\mu - 1}\). Substituting \(R = 10\text{ cm}\) and \(f = 30\text{ cm}\), we get \(30 = \frac{10}{\mu - 1}\) which gives \(\mu - 1 = \frac{1}{3}\). Therefore, \(\mu = \frac{4}{3}\).

Question 96: easy

Assertion (A): A lens has two principal focal lengths which may be different in magnitude.


Reason (R): The distance of both principal focus from optical centre of lens depend on the two radii of curvature of the lens. Distance of both principal focus from optical centre a lens are same only if radii of curvature of both sides of lens are same.


 

1. Both (A) & (R) are true and the (R) is the correct explanation of the (A)
2. Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
3. (A) is true but (R) is false
4. Both (A) and (R) are false
View Answer

Assertion (A) is true if the lens is in different media on either side. Reason (R) is false because for a thin lens in the same medium, magnitudes of focal lengths are always equal, irrespective of the equality of radii of curvature.

Question 97: easy

Assertion (A): A simple microscope may have different magnification for different persons.


Reason (R): All persons must have the same near point distance of \(25\text{ cm}\).


 

1. Both (A) & (R) are true and the (R) is the correct explanation of the (A)
2. Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
3. (A) is true but (R) is false
4. Both (A) and (R) are false
View Answer

Assertion (A) is true as magnification depends on individual near point, which varies. Reason (R) is false as the near point varies for different individuals and is not universally \(25\text{ cm}\).

Question 98: easy

Assertion (A): If an object placed on the optic axis of a lens is illuminated by white light, then image formed will be coloured and not exactly white.


Reason (R): The lens has different focal lengths for different colours.


 

1. Both (A) & (R) are true and the (R) is the correct explanation of the (A)
2. Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
3. (A) is true but (R) is false
4. Both (A) and (R) are false
View Answer

Assertion (A) is true due to chromatic aberration. Reason (R) is true and correctly explains (A) because the refractive index of lens material varies with wavelength, causing different focal lengths for different colors.

Question 99: easy

Assertion (A): Paraxial rays are always parallel to the principal axis.


Reason (R): A parallel beam parallel to principal axis converges at the focal point.


 

1. Both (A) & (R) are true and the (R) is the correct explanation of the (A)
2. Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
3. (A) is true but (R) is false
4. Both (A) and (R) are false
View Answer

Assertion (A) is false; paraxial rays are simply close to the axis, not necessarily parallel. Reason (R) is also false because due to spherical aberration, a real parallel beam does not perfectly converge to a single focal point.

Question 100: easy

Assertion (A): The image focus (\(2^{\text{nd}}\) focus) and the object focus (\(1^{\text{st}}\) focus) are on the opposite side of the biconvex or biconcave lens.


Reason (R): The radii of curvature of a biconvex lens and biconcave lens are on the opposite side of the lens.


 

1. Both (A) & (R) are true and the (R) is the correct explanation of the (A)
2. Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
3. (A) is true but (R) is false
4. Both (A) and (R) are false
View Answer

Assertion (A) is true; the two principal focal points are on opposite sides of the lens. Reason (R) is true, describing the geometric arrangement of the centers of curvature. However, (R) does not explain (A).