Solution:
For normal incidence on the first face, the angle of refraction \(r_1 = 0\), which implies \(r_2 = A\). Applying Snell's law at the second face for small angles, \(e \approx \mu r_2 = \mu A\), giving \(A \approx \frac{e}{\mu}\).
A ray of light is incident normally on one face of a thin prism of refractive index \(mu\) and emerges at an angle (e) from the normal. Angle of prism \(A\) is nearly
Leave a Reply