Combination of Resistors

Practice Questions:

Question 1: easy

The resistance of two conductors in series is 40 Ω and this becomes 7.5 Ω in parallel, the resistances of conductors are:

1. 20 Ω, 20 Ω

2. 10 Ω, 30 Ω

3. 15 Ω, 25 Ω

4. 18 Ω, 22 Ω

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Question 2: easy

Which of the following is not possible by combination of four resistors each equal to \(8 \Omega \)?

1. \(20 \Omega \)

2. \(32/3 \Omega\)

3. \(1 \Omega\)

4. \(8 \Omega\)

View Answer

With four \(8 \Omega \) resistors, the minimum possible equivalent resistance is when all four are in parallel: \(R_{min} = 8/4 = 2 \Omega\). Thus, \(1\Omega\) is impossible.

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