Work Energy and Power - NEET Physics Questions
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Work Energy and Power

Question 11: moderate

Potential energy of a particle at position x is given by U = x² – 5x. Which of the following is equilibrium position of the particle?

1. x = 0
2. x = 2.5 m
3. x = 5 m
4. x = 7.5 m
View Answer

For Equilibrium,

dU/dx = 0

⇒ d(x²-5x)/dx=0

⇒ 2x-5 = 0

⇒ x =2.5 m

Question 12: moderate

In a conservative field, the potential energy U as a function of position x is given by U = x². Then the corresponding conservative force is given by

1. x
2. 2x
3. -x
4. -2x
View Answer

By definition Force F = -dU/dx, so 

F = - d(x²)/dx= -2x

Question 13: moderate

In a certain field, the potential energy is U = ax² – bx³, where a and b constants. The particle is in stable equilibrium at x equal to

1. zero
2. a/3b
3. 2a/3b
4. 2a/b
View Answer

Potential Energy is U = ax² – bx³. For Equilibrium F = -dU/dx

⇒ dU/dx= 2ax- 3bx²=0

⇒ x = 2a/3b

Question 14: moderate

An engine pumps 400 kg of water through height of 10 m in 40 s. Find the power of the engine if its efficiency is 80% (g = 10 m/s²).

1. 500 W
2. 750 W
3. 1000 W
4. 1250 W
View Answer

Power = Work Done / Time Taken

Here , Work Done = 400 ×10 ×10 J = 40000 J

Time Taken = 40 sec , So, 

Power = 40000/40 = 1000 W= 1 KW

Efficiency = Output Power/ Input Power × 100

80 = 1000/ Input Power × 100

⇒Input Power = 1250 W= 1.25 KW

Question 15: moderate

A block of mass 4 kg is pulled along a smooth inclined plane of inclination 30° with constant velocity 3 m/s as shown, power delivered by the force is

1. 40 watt
2. 20 watt
3. 60 watt
4. 30 watt
View Answer

As the object is not moving with constant speed net force on it is zero.

so F = mg sin 30 °= 4 × 10 × ½= 20 N

Power is Dot product of force and velocity. So, P = 20 × 3 = 60 W

Question 16: moderate

Water from a stream is falling on the blades of a turbine at the rate of 100 kg/s. If the height of the stream is 100 m, then power delivered to turbine is

1. 100 kW
2. 0.1 kW
3. 10 kW
4. 1 kW
View Answer

Power is Rate of doing work. 

Power = mgh/t= (m/t)gh= 100 × 10 × 100 = 100 kW

Question 17: moderate

A body is being moved from rest along a straight line by a machine delivering constant power. The speed of  body in time t is proportional to

1. t
2.
3.
4. 1/t
View Answer

Power = Constant (K)

F.v= K 

⇒m.(dv/dt).v = K

⇒m.v.dv = K.dt

Integrating we get,

⇒∫m.v.dv=∫K.dt 

⇒ mv²/2 = Kt

so, V α  t½

Question 18: moderate

A body of mass m is raised to height h from ground along three different paths viz I, II and III against gravity as shown below. If WI, WII and WIII are the work done along the respective paths of I, II and III, then the correct option is (there is no nonconservative force)

1. WIII > WII > WI
2. WI > WII > WIII
3. WII > WI > WIII
4. WI = WII = WIII
View Answer

Work done by conservative force is independent of path taken so, WI = WII = WIII

Question 19: moderate

A bullet having mass 10 g is fired towards a fixed wooden block with velocity of 30 m/s. If it comes out of the block with velocity of 20 m/s, then the total work done by the resistive forces is

1. + 4.5 J
2. - 4.5 J
3. +2.5 J
4. - 2.5 J
View Answer

By Work Energy Theorem, 

Work Done= Change in Kinetic Energy

⇒W= ½×(10/ 1000) × ( 20²- 30²) = -500/200= - 2.5 J

Question 20: moderate

A uniform chain has a mass m and length l. It is held on a frictionless table with one-sixth of its length hanging over the edge. The work done in just pulling the hanging part back on the table is

1. mgl/72
2. mgl/36
3. mgl/12
4. mgl/6
View Answer

mass of hanging portion = m/6

Potential energy of handing portion = m/6×g×(-l/12)= -mgl/72

Work done by external agent is negative of change is Potential Energy = mgl/72