Reflection by Plane Mirror

Practice Questions:

Question 1: easy

The reflecting surfaces of two mirrors M1 and M2 are at an angle θ as shown in the figure. A ray of light is incident on M1. The emerging ray intersects , the incident ray at an angle Φ. Then,

1. Φ = θ

2. Φ = 180 - θ

3. Φ = 90 - θ

4. Φ = 180 - 2θ

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Question 2: easy

Assertion (A): Keeping a point object fixed, if a plane mirror is moved, the image will also move.

Reason (R): In case of a plane mirror, distance of object and its image is equal from any point on the mirror.

1. Both (A) & (R) are true and the (R) is the correct explanation of the (A)

2. Both (A) & (R) are true but the (R) is not the correct explanation of the (A)

3. (A) is true but (R) is false

4. Both (A) and (R) are false

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Assertion (A) is true; the image position is relative to the mirror, so it moves with the mirror. Reason (R) is true as per the property of plane mirrors, where \(OP = IP\). (R) correctly explains (A) as image movement maintains this property.

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Question 3: easy

Assertion (A): If there is relative motion between a point object & a plane mirror then there must be relative motion between object and image formed by mirror.

Reason (R): If the gap between object and mirror will change, the gap between object and image remains same.

1. Both (A) & (R) are true and the (R) is the correct explanation of the (A)

2. Both (A) & (R) are true but the (R) is not the correct explanation of the (A)

3. (A) is true but (R) is false

4. Both (A) and (R) are false

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Assertion A is true because if the object moves relative to the mirror, its image also moves, causing relative motion between object and image. Reason R is false because for a plane mirror, the object-image gap is twice the object-mirror gap, so if the object-mirror gap changes, the object-image gap also changes.

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Question 4: easy

Assertion (A): A parallel beam of light travelling in air can be displaced laterally by a parallel transparent slab by distance more than the thickness of the plate.

Reason (R): The lateral displacement of light travelling in air increases with fall in value of refractive index of slab.

1. Both (A) & (R) are true and the (R) is the correct explanation of the (A)

2. Both (A) & (R) are true but the (R) is not the correct explanation of the (A)

3. (A) is true but (R) is false

4. Both (A) and (R) are false

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Assertion A is false as the lateral displacement of light through a parallel slab is always less than or equal to its thickness. Reason R is false because lateral displacement decreases as the refractive index of the slab falls.

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Question 5: easy

Assertion (A): A virtual image formed by plane mirror may be inverted.

Reason (R): Longitudinal magnification in this case of plane mirror is \(-1\).

1. Both (A) & (R) are true and the (R) is the correct explanation of the (A)

2. Both (A) & (R) are true but the (R) is not the correct explanation of the (A)

3. (A) is true but (R) is false

4. Both (A) and (R) are false

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Assertion A is true because a plane mirror forms a laterally inverted image. Reason R is true because for a plane mirror, longitudinal magnification \(m_L = - (v/u)^2 = -1\). However, longitudinal magnification does not explain lateral inversion.

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Question 6: easy

Assertion (A): The minimum length of mirror required to form complete image of man of height \(H) is \(H/2\).

Reason (R): Image of an object is obtained if incident light ray reaches the reflecting surface.

1. (1) Both (A) & (R) are true and the (R) is the correct explanation of the (A)

2. (2) Both (A) & (R) are true but the (R) is not the correct explanation of the (A)

3. (3) (A) is true but (R) is false

4. (4) Both (A) and (R) are false

View Answer

The minimum length of a plane mirror to see a full image of a person of height \(H) is \(H/2\). Image formation occurs when light rays reach and reflect from a surface. Both statements are true, but R is a general principle and does not explain the specific \(H/2\) relation.

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Question 7: easy

Assertion (A): Any ray of light suffers a deviation of \(180° – 2i\) after one reflection from plane mirror.

Reason (R): For normal incidence of light on the plane mirror deviation is zero.

1. Both (A) & (R) are true and the (R) is the correct explanation of the (A)

2. Both (A) & (R) are true but the (R) is not the correct explanation of the (A)

3. (A) is true but (R) is false

4. Both (A) and (R) are false

View Answer

For a plane mirror, the angle of deviation \(delta\) for an incident ray is given by \(delta = 180° - 2i\), where \(i\) is the angle of incidence. Thus, Assertion (A) is true. For normal incidence, \(i=0\), and the ray retraces its path, meaning its direction is reversed. This corresponds to a deviation of \(180°\), not zero. Hence, Reason (R) is false.

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Question 8: easy

Assertion (A): In case of single refraction by plane surface image and object are on the same side.

Reason (R): If object is real, image will be virtual and vice-versa.

1. Both (A) & (R) are true and the (R) is the correct explanation of the (A)

2. Both (A) & (R) are true but the (R) is not the correct explanation of the (A)

3. (A) is true but (R) is false

4. Both (A) and (R) are false

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For a plane refracting surface, a real object always forms a virtual image. This virtual image is formed on the same side of the plane surface as the object itself, as light rays appear to diverge from it after refraction.

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Question 9: easy

Assertion (A): Law of reflection is applicable for all type of mirrors.

Reason (R): Rays which are parallel to principal axis are known as paraxial rays.

1. Both (A) & (R) are true and the (R) is the correct explanation of the (A)

2. Both (A) & (R) are true but the (R) is not the correct explanation of the (A)

3. (A) is true but (R) is false

4. Both (A) and (R) are false

View Answer

Laws of reflection are fundamental and apply to all mirrors, so (A) is true. Paraxial rays are rays close and parallel to the principal axis, so (R) is true. (R) defines a term, it does not explain the universality of reflection laws.

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Question 10: easy

Assertion (A): It is never possible to produce a real image using a plane mirror.

Reason (R): Radius of curvature of a plane mirror is negative.

1. Both (A) & (R) are true and the (R) is the correct explanation of the (A)

2. Both (A) & (R) are true but the (R) is not the correct explanation of the (A)

3. (A) is true but (R) is false

4. Both (A) and (R) are false

View Answer

Assertion (A) is true as plane mirrors always form virtual images.
Reason (R) is false because the radius of curvature of a plane mirror is infinite.
Therefore, (A) is true and (R) is false.

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