In the product \(\vec{F} = q(\vec{v} \times \vec{B}) = q \vec{v} \times (B_x \hat{i} + B_y \hat{j} + B_0 \hat{k})\), for \(q = 1\) and \(\vec{v} = 2\hat{i} + 4\hat{j} + 6\hat{k}\) and \(\vec{F} = 4\hat{i} – 20\hat{j} + 12\hat{k}\). What will be the complete expression for \(vec{B}\)?
1. \(6\hat{i} + 6\hat{j} - 8\hat{k}\)
2. \(-8\hat{i} - 8\hat{j} - 6\hat{k}\)
3. \(-6\hat{i} - 6\hat{j} - 8\hat{k}\)
4. \(8\hat{i} + 8\hat{j} - 6\hat{k}\)
View Answer
Using the relation \(\vec{F} = \vec{v} \times \vec{B}\), we compare vector components: \(4\hat{i} - 20\hat{j} + 12\hat{k} = (4 B_0 - 6 B_y)\hat{i} - (2 B_0 - 6 B_x)\hat{j} + (2 B_y - 4 B_x)\hat{k}\). Testing the values in Option C gives \(B_x = -6\, B_y = -6\, B_0 = -8\), which completely satisfies all equations.
A uniform electric field and a uniform magnetic field are acting along the same direction in a certain region. If an electron is projected in the region such that its velocity is pointed along the direction of fields, then the electron
1. Speed will decrease
2. Speed will increase
3. Will turn towards right of direction of motion
4. Will turn towards left of direction of motion
View Answer
The magnetic force on the electron is \(F_m = q(\vec{v} \times \vec{B}) = 0\) since they are parallel. The electric force is \(F_e = -eE\), which acts opposite to its velocity, causing the electron to decelerate and decrease its speed.