Motional EMF - NEET Physics Questions
Question 11: moderate

A wheel with ten metallic spockes each 0.50 m long is rotated with a speed of 120 rev/min in a plane normal to the earth’s magnetic field at the place. If the magnitude of the field is 0.4 Gauss, the induced e.m.f. between the axle and the rim of the wheel is equal to :

 

1. \[1.256\times 10^{-3} V\]
2. \[6.28\times 10^{-4} V\]
3. \[1.256\times 10^{-4} V\]
4. \[6.28\times 10^{-5} V\]
View Answer

Using the formula for induced e.m.f. in a rotating conductor:

$$e = \frac{1}{2} B \omega L^2 = \frac{1}{2} B (2\pi f) L^2$$

Substituting

$$e = \frac{1}{2} \times (0.4 \times 10^{-4}) \times (4\pi) \times (0.5)^2 = 6.28 \times 10^{-5}\text{ V}$$