Combination of Resistors - NEET Physics Questions
← Back to Current Electricity

Combination of Resistors

Question 11: moderate

A and B are two points on a uniform ring of resistance R. The ∠ACB = θ, where C is the centre of the ring. The equivalent resistance between A and B is

1. \[R\frac{2\pi-\theta}{4\pi}\]
2. \[R\left( 1-\frac{\theta}{2\pi} \right)\]
3. \[R\frac{\theta}{2\pi}\]
4. \[\frac{R}{4\pi^{2}}\left( 2\pi-\theta \right)\theta\]
View Answer
Question 12: moderate

The equivalent resistance of the network shown in the figure between the points A and B is :-

 

1. 6 Ω
2. 8 Ω
3. 16 Ω
4. 24 Ω
View Answer
Question 13: moderate

The effective resistance across the points A and I is :-

1. 2 Ω
2. 1 Ω
3. 0.5 Ω
4. 5 Ω
View Answer
Question 14: moderate

Twelve resistors each of resistance 1 Ω are connected in the circuit shown in the figure. Net resistance between points A and H would be :-

1. 5/3 Ω
2. 1 Ω
3. 3/4 Ω
4. 7/6 Ω
View Answer
Question 15: moderate

In the given network of resistors, each of resistance R ohm, the equivalent resistance between points A and B is :-

1. 5 R
2. 2R/3
3. 3R/5
4. R/2
View Answer
Question 17: difficult

Find the equivalent resistance between point A and B. (all resistors are in ohms)

1. 5 Ω
2. 4 Ω
3. 3 Ω
4. 6 Ω
View Answer
Question 18: easy

Which of the following is not possible by combination of four resistors each equal to \(8 \Omega \)?

1. \(20 \Omega \)
2. \(32/3 \Omega\)
3. \(1 \Omega\)
4. \(8 \Omega\)
View Answer

With four \(8 \Omega \) resistors, the minimum possible equivalent resistance is when all four are in parallel: \(R_{min} = 8/4 = 2 \Omega\). Thus, \(1\Omega\) is impossible.