Work Done by Constant and Variable Forces - NEET Physics Questions
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Work Done by Constant and Variable Forces

Question 1: easy

A force of (3ˆi + 4ˆj)N acts on a body and displaced it by (3ˆi + 4ˆj)m . The work done by the force is

1. 9 J
2. 16 J
3. 25 J
4. 50 J
View Answer

By Definition of Work ,

Work Done = F.S= (3ˆi + 4ˆj).(3ˆi + 4ˆj)= 9+16 =25 J

Question 2: easy

When the bob of a simple pendulum swings, the work done by tension in the string is

1. + ve
2. - ve
3. maximum
4. zero
View Answer

As Angle between tension force and displacement is 90°. Work done is zero

Question 3: easy

Assertion: Work done by a force depends on frame of reference.


Reason: Force and displacement both depend on frame of reference.

1. Both Assertion and Reason are true and Reason is the correct explanation of Assertion.
2. Both Assertion and Reason are true but Reason is not correct explanation of Assertion.
3. Assertion is true but Reason is false.
4. Assertion and Reason are false.
View Answer

Work done depends on the frame of reference because displacement depends on the frame of reference. However, real forces do not depend on the frame of reference. Hence, the Assertion is true but the Reason is false.

Question 4: easy

A force \( \vec{F} = (3x\hat{i} + 4\hat{j})\text{ Newton} \) (where \( x \) is in metres) acts on a particle which moves from a position \( (2\text{ m}, 3\text{ m}) \) to \( (3\text{ m}, 0\text{ m}) \). Then the work done is:

1. \( 7.5\text{ J} \)
2. \( -12\text{ J} \)
3. \( -4.5\text{ J} \)
4. \( +4.5\text{ J} \)
View Answer

The work done by the force is \( W = \int_{2}^{3} 3x \, dx + \int_{3}^{0} 4 \, dy = \left[ \frac{3x^2}{2} \right]_2^3 + [4y]_3^0 = 7.5 - 12 = -4.5\text{ J} \).