Kinetic Energy and Momentum

Practice Questions:

Question 1: moderate

Two masses of 1 g and 4 g are moving with equal kinetic energies. The ratio of the magnitudes of their linear momenta is

1. 1:2

2. √2:1

3. 4:1

4. 1:16

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Kinetic Energy is given by K = ½mv² and Momentum is P=m.v, relation between kinetic energy and momentum is

K= P²/2m so P=√(2mK)

So P1/P2= √(m1)/√(m2)= √1/√4 = 1:2

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Question 2: moderate

If the kinetic energy of a body is increased by 300%, its momentum will increase by :

1. 100%

2. 150%

3. 200%

4. 400%

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Relation between Kinetic Energy and Momentum is

P = √(2mK)

When kinetic energy is increased by 300 % it becomes 4K so new momentum is

P1= √(2m.4K) =2P

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Question 3: moderate

If the kinetic energy of a body is increased by 3%, its momentum will increase by :

1. 1 %

2. 1.5 %

3. 3 %

4. 4.5 %

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K = P²/2m so,

∇K/K=2∇P/P

Solving We get , ∇P/P = 1.5%

Question 4: moderate

The graph between √E and 1/p is (E = kinetic energy and p = momentum):

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