The angle of minimum deviation for a prism is 40° and the angle of the prism is 60°. The angle of incidence in the position will be
A ray falls on a prism ABC (AB = BC) and travels as shown in figure. The minimum refractive index of the prism material should be

For the situations shown in the figure, determine the angle by which the mirror should be rotated, so that the light ray will retrace its path after refraction through the prism and reflection from the mirror ?

Variation of angle of deviation δ versus angle of incidence for a prism is given the figure. The value of refractive index of prism :

Refractive index of a prism is \(cosec(A/2)\). Then minimum angle of deviation is :
Using the prism formula: \(mu = \frac{sin((A+\delta_m)/2)}{sin(A/2)}\). Substituting \(mu = cosec(A/2) =\frac{1}{sin(A/2)}\), we get \(sin((A+\delta_m)/2) = 1 ⇒ (A+\delta_m)/2 = 90^0 ⇒ \delta_m = 180^0 - A\).