Oscillation - NEET Physics Questions
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Oscillation

Question 1: easy

A body is executing simple harmonic motion with frequency \(n\), the frequency of its potential energy is

1. \(4n\)
2. \(n\)
3. \(2n\)
4. \(3n\)
View Answer

In SHM, potential energy oscillates with twice the frequency of displacement. Since the displacement frequency is \(n\), the potential energy frequency is \(2n\).

Question 2: easy

A vertical spring block system is made to oscillate.


Assertion (A): Its time period on earth is more than that on the moon.


Reason (R): Its extension on moon (in equilibrium) is more than that on the earth.


 

1. Both (A) & (R) are true and the (R) is the correct explanation of the (A)
2. Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
3. (A) is true but (R) is false
4. Both (A) and (R) are false
View Answer

The time period of a vertical spring-block system is \(T = 2\pi \sqrt{\frac{m}{k}}\), which is independent of gravity (g). So (A) is false. The equilibrium extension is \(x_{eq} = \frac{mg}{k}\). Since \(g_{moon} < g_{earth}\), then \(x_{eq,moon} < x_{eq,earth}\). So (R) is also false.

Question 3: easy

Assertion (A): Total mechanical energy in SHM is conserved.


Reason (R): Kinetic energy of SHM at mean position is equal to potential energy at ends for a particle moving in SHM.


 

1. Both (A) & (R) are true and the (R) is the correct explanation of the (A)
2. Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
3. (A) is true but (R) is false
4. Both (A) and (R) are false
View Answer

In ideal SHM, total mechanical energy is conserved because the restoring force is conservative. So (A) is true. At the mean position, \(KE_{max} = \frac{1}{2}m(A\omega)^2\), and at the ends, \(PE_{max} = \frac{1}{2}kA^2 = \frac{1}{2}m\omega^2A^2\). Thus, \(KE_{mean} = PE_{ends}\). So (R) is true. However, (R) describes a consequence of energy conservation, not the fundamental reason for it.

Question 4: easy

Assertion (A): A SHM may be assumed as composition of many SHM’s.


Reason (R): Superposition of many SHM’s (along same line) of same frequency will be a SHM.


 

1. Both (A) & (R) are true and the (R) is the correct explanation of the (A)
2. Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
3. (A) is true but (R) is false
4. Both (A) and (R) are false
View Answer

Assertion (A) states that an SHM can be viewed as a composition of multiple SHMs. Reason (R) states that the superposition of multiple SHMs along the same line and with the same frequency results in another SHM.


Both statements are true, and (R) provides the explanation for how (A) can be possible.

Question 5: easy

Assertion (A): Displacement-time equation of a particle moving along \(x\)-axis is \(x = 4 + 6 sin\omega t\). Under this situation, motion of particle is not simple harmonic.


Reason (R): \(\frac{d^2x}{dt^2}\) for the given equation is not proportional to \(-x\).


 

1. Both (A) & (R) are true and the (R) is the correct explanation of the (A)
2. Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
3. (A) is true but (R) is false
4. Both (A) and (R) are false
View Answer

For SHM, \(a = -\omega^2 (x-x_0)\). Given \(x = 4 + 6 sin\omega t\), the equilibrium position is \(x_0=4\). The acceleration is \(\frac{d^2x}{dt^2} = -\omega^2 (x-4)\). If SHM is strictly defined as \(a \propto -x\) (equilibrium at origin), then (A) is true. (R) is also true as \(\frac{d^2x}{dt^2}\) is proportional to \(-(x-4)\), not \(-x\). (R) explains (A).

Question 6: easy

Assertion (A): For a particle performing SHM, its speed decreases as it goes away from the mean position.


Reason (R): In SHM, the acceleration is always opposite to the velocity of the particle.


 

1. Both (A) & (R) are true and the (R) is the correct explanation of the (A)
2. Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
3. (A) is true but (R) is false
4. Both (A) and (R) are false
View Answer

As a particle in SHM moves from the mean to extreme position, its speed decreases as the restoring force opposes motion. So (A) is true. Acceleration is always directed towards the equilibrium. When moving towards equilibrium, velocity and acceleration are in the same direction, so (R) is false.

Question 7: easy

Assertion (A): Motion of a ball bouncing elastically in vertical direction on a smooth horizontal floor is a periodic motion but not an SHM.


Reason (R): Motion is SHM when restoring force is proportional to displacement from mean position.


 

1. Both (A) & (R) are true and the (R) is the correct explanation of the (A)
2. Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
3. (A) is true but (R) is false
4. Both (A) and (R) are false
View Answer

Periodic motion repeats over time. SHM requires a restoring force proportional to displacement \(F = -kx\). A bouncing ball experiences gravitational force \(F=mg\) (constant) and impulsive forces upon impact, not a linear restoring force. Hence, it's periodic but not SHM, and the reason correctly defines SHM.

Question 8: easy

Assertion (A): A particle, simultaneously subjected to two simple harmonic motions of same frequency and same amplitude, will perform SHM only if the two SHM’s are in the same direction.


Reason (R): A particle, simultaneously subjected to two simple harmonic motions of same frequency and same amplitude, perpendicular to each other the particle can be in uniform circular motion.


 

1. Both (A) & (R) are true and the (R) is the correct explanation of the (A)
2. Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
3. (A) is true but (R) is false
4. Both (A) and (R) are false
View Answer

Assertion (A) is true: Superposition of parallel SHMs results in SHM. Assertion (R) is true: Perpendicular SHMs of same frequency and amplitude with \(frac{pi}{2}\) phase difference result in UCM. However, (R) explains a scenario where SHM is not formed along a line, not why (A) is true.

Question 9: easy

Assertion (A): \(x = A sin \omega t\) & \(y = B cos \omega t\) In the above co-ordinates particle moves in elliptical path.


Reason (R): A periodic motion can always be expressed as a sum of infinite number of harmonic motions with appropriate amplitude.


 

1. Both (A) & (R) are true and the (R) is the correct explanation of the (A)
2. Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
3. (A) is true but (R) is false
4. Both (A) and (R) are false
View Answer

Assertion (A) is true: From \(x = A sin \omega t\) and \(y = B cos \omega t\), we get \(\left( \frac{x}{A} \right)^2 + \left( \frac{y}{B} \right)^2 = 1\), which is an ellipse. Reason (R) is true: Fourier's theorem states any periodic motion can be decomposed into harmonic components. However, (R) does not explain why the given equations describe an ellipse.

Question 10: easy

Assertion (A): Under forced oscillation external periodic force apply to sustain the motion.


Reason (R): Under forced oscillation phase of harmonic motion of the particle differs from the phase of the driving force.


 

1. Both (A) & (R) are true and the (R) is the correct explanation of the (A)
2. Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
3. (A) is true but (R) is false
4. Both (A) and (R) are false
View Answer

Assertion (A) is true: Forced oscillations involve an external periodic force to maintain motion. Reason (R) is true: In forced oscillations, a phase difference exists between the driving force and the particle's motion. (R) describes a property of forced oscillations, but doesn't explain the reason for applying the external force as stated in (A).