Force Acting on Moving Charges - NEET Physics Questions
← Back to Magnetic Effects of Current

Force Acting on Moving Charges

Question 1: easy

A proton, deutron and α-particle are accelerated by same potential, enters in uniform
magnetic field perpendicularly. Ratio of radii of circular path respectively :

1. 1: √2 : √2
2. 2 : 2 : 1
3. 1 : 2 : 1
4. 1 : 1 : 1
View Answer
Question 2: easy

Two particles X and Y having equal charges, after being accelerated through the same potential
difference, enter a region of uniform magnetic field and describe circular paths of radii R1 and
R2 respectively. The ratio of masses of X and Y is :

1. \[\left( R_{1}/R_{2} \right)^{1/2}\]
2. \[\left( R_{2}/R_{1} \right)\]
3. \[\left( R_{1}/R_{2} \right)^{2}\]
4. \[\left( R_{1}/R_{2} \right)\]
View Answer
Question 3: easy

A beam of electrons is projected horizontally to the right. A straight conductor carrying a current is supported parallel to the electron beam and above it. If the current in the conductor is from left to right, what will be the effect on the electron beam ?

1. The electron beam will be pulled upwards
2. The electron beam will be pulled downwards
3. The electron beam will be retarded
4. The electron beam will be speeded up towards the right
View Answer
Question 4: easy

A uniform electric field and a uniform magnetic field are produced, pointed in the same direction. An electron is projected with its velocity pointed in the same direction :

1. the electron will turn to its right
2. the electron will turn to its left
3. the electron velocity will increase in magnitude
4. the electron velocity will decrease in magnitude
View Answer
Question 5: easy

An electron moving with a speed u along the positive x-axis at y = 0 enters in a region of
uniform magnetic field \[\overrightarrow{B}=-B_{0}\hat{k}\] which exists to
the right of y-axis. The electron exits from the region after some time with speed v at coordinate
y, then :

1. v > u, y < 0
2. v = u, y > 0
3. v > u, y > 0
4. v = u, y < 0
View Answer
Question 6: easy

When a charged particle moving with velocity \(\overrightarrow{v}\)is subjected to a magnetic field of induction                 \(\overrightarrow{B}\) , the force on it is non-zero. This implies the :

1. angle between \[\overrightarrow{v}\] and \[\overrightarrow{B}\] is necessary 90º
2. angle between \[\overrightarrow{v}\] and \[\overrightarrow{B}\] can have at value other than 90º
3. angle between \[\overrightarrow{v}\] and \[\overrightarrow{B}\] can have at value other than zero and 180º
4. angle between \[\overrightarrow{v}\] and \[\overrightarrow{B}\] is either zero or 180º
View Answer
Question 7: easy

An eΘ is moving in North direction & magnetic field at this place is along upward direction then
eΘ will be deviate towards :

 

1. East
2. West
3. North
4. South
View Answer
Question 8: easy

A uniform electric field and a uniform magnetic field are acting along the same direction in a certain region. If an electron is projected in the region such that its velocity is pointed along the direction of fields, then the electron

1. Speed will decrease
2. Speed will increase
3. Will turn towards right of direction of motion
4. Will turn towards left of direction of motion
View Answer

Since the velocity \(vec{v}\) is parallel to the magnetic field \(vec{B}\), the magnetic force is zero. The electric field exerts a force opposite to the direction of velocity on the negatively charged electron, decreasing its speed.

Question 9: easy

Which of the following charges has the maximum frequency of revolution in a uniform transverse magnetic field?

1. a proton
2. an alpha particle
3. an electron
4. a neutron
View Answer

Frequency of revolution in a magnetic field is given by \(f = \frac{qB}{2\pi m}\). Since the electron has the highest charge-to-mass ratio \(q/m\) among the charged particles, it has the maximum frequency.

Question 10: easy

A particle of mass \(M\) and charge \(Q\) moving with velocity \(\vec{v}\) describes a circular path of radius \(R\) when subjected to a uniform transverse magnetic field of induction \(B\). The work done by the field when the particle completes one full circle is:

1. \(BQv2\pi R\)
2. \(\left(\frac{M v^2}{R}\right) 2\pi R\)
3. Zero
4. \(BQ2\pi R\)
View Answer

The magnetic force \(\vec{F} = Q(\vec{v} \times \vec{B})\) is always perpendicular to the velocity \(\vec{v}\). Therefore, power \(P = \vec{F} \cdot \vec{v} = 0\), meaning the work done is always zero.