Linear Momentum and Second Law of Motion - NEET Physics Questions
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Linear Momentum and Second Law of Motion

Question 11: easy

A projectile is thrown at a speed of \(100\text{ m/s}\) at an angle of \(37^\circ\) above the horizontal. At the highest point the projectile breaks into two parts of mass ratio \(1 : 3\), the smaller coming to rest. Find the speed of the second piece.

1. \(320/3\text{ m/s}\)
2. \(310/3\text{ m/s}\)
3. \(800/3\text{ m/s}\)
4. \(1120/3\text{ m/s}\)
View Answer

At the highest point, velocity is horizontal: \(v_x = u\cos(37^\circ) = 100 \times 0.8 = 80\text{ m/s}\). By conservation of linear momentum along the horizontal: \(m v_x = m_1 v_1 + m_2 v_2\). Here \(m_1 = m/4\) (comes to rest, \(v_1 = 0\)) and \(m_2 = 3m/4\). Thus, \(m(80) = \frac{3m}{4} v_2\), which gives \(v_2 = \frac{320}{3}\text{ m/s}\).

Question 12: easy

Assertion (A): Two smooth blocks are kept on a smooth inclined plane such that one block is kept over other. When a force is applied on upper block acceleration of lower block is unaffected.


Reason (R): Acceleration of a block on smooth inclined plane is \(g sin(\theta)\).

1. (1) Both (A) & (R) are true and the (R) is the correct explanation of the (A)
2. (2) Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
3. (3) (A) is true but (R) is false
4. (4) Both (A) and (R) are false
View Answer

Assertion (A) is true: Since both blocks are on smooth surfaces (implying no friction between blocks), a force applied *only* to the upper block will not be transmitted horizontally to the lower block. The upper block will slide over the lower. The lower block will continue to accelerate down the smooth inclined plane solely due to gravity.


Reason (R) is true: The acceleration of any block on a smooth inclined plane (where \(theta\) is the angle of inclination) is indeed \(g sin(theta)\), assuming no other forces. Reason (R) states a fact about acceleration on an inclined plane. While it describes the acceleration of the lower block, it does not explain *why* the force on the upper block has no effect on it (which is due to the lack of friction between them).


Therefore, (A) and (R) are true, but (R) is not the correct explanation of (A).

Question 13: easy

Assertion (A): If a body has no acceleration, then there are no forces acting on it.


Reason (R): If a single force acts on a body, then the body will move in the direction of force.


 

1. Both (A) & (R) are true and the (R) is the correct explanation of the (A)
2. Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
3. (A) is true but (R) is false
4. Both (A) and (R) are false
View Answer

Assertion (A) is false; zero acceleration implies zero \(\text{net}\) force, not zero individual forces. Reason (R) is false; a single force causes \(text{acceleration}\) in its direction, not necessarily motion in that direction if initial velocity is present.

Question 14: easy

A frame of reference A is moving rectilinearly and uniformly with a velocity \(\vec{u}\) with respect to an inertial frame B. A body is moving with velocity \(\vec{v}\) and acceleration \(\vec{a}\) in an inertial system B.


Assertion (A): When we use Newtons second Law in frame B we write \( \Sigma \vec{F}_{net} = m\vec{a} \). Now when we use the same in frame A we will write exactly same \(\Sigma \vec{F}_{net}\) and \(\vec{a}\) .


Reason (R): All inertial system are equally suitable for the description of physical phenomenon.

1. Both (A) & (R) are true and the (R) is the correct explanation of the (A)
2. Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
3. (A) is true but (R) is false
4. Both (A) and (R) are false
View Answer

Frame A, moving with constant velocity relative to inertial frame B, is also an inertial frame. Newton's second law \( \Sigma \vec{F}_{net} = m\vec{a} \) holds in all inertial frames with the same forces and acceleration. This is because all inertial systems are equally suitable for describing physical phenomena. Both A and R are true, and R explains A.