Alternating Current - NEET Physics Questions
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Alternating Current

Question 21: easy

The peak voltage of the AC source is equal to

1. The value of voltage applied to the circuit
2. The rms value of the source
3. \(\sqrt{2}\) times the rms value of the AC source
4. \(\frac{1}{\sqrt{2}}\) times the average value of the AC source
View Answer

For a sinusoidal AC voltage source, the relation between peak voltage \(V_0\) and root-mean-square voltage \(V_{\text{rms}}\) is \(V_0 = \sqrt{2}V_{\text{rms}}\).

Question 22: easy

A series LCR circuit contains a capacitor of capacitance \(10^{-6}\text{ F}\) and an inductor of inductance \(10^{-4}\text{ H}\). The resonant frequency of the circuit will be

1. \[10^5\text{ Hz}\]
2. \[10\text{ Hz}\]
3. \[\frac{10^5}{2\pi}\text{ Hz}\]
4. \[\frac{10}{2\pi}\text{ Hz}\]
View Answer

The resonant frequency is \[f = \frac{1}{2\pi\sqrt{LC}} = \frac{1}{2\pi\sqrt{10^{-4} \times 10^{-6}}} = \frac{10^5}{2\pi}\text{ Hz}\].

Question 23: easy

Power consumed in A.C circuit is zero then the ac source could be connected to

1. Resistor only
2. Inductor only
3. Capacitor only
4. Both (2) and (3)
View Answer

The average power consumed in an AC circuit is given by \( P_{avg} = V_{rms} I_{rms} \cos \phi \). For a purely inductive or purely capacitive circuit, the phase difference \( \phi = 90^\circ \), which makes the power factor \( \cos \phi = 0 \), resulting in zero power consumption.

Question 24: easy

Consider an a.c circuit having resistor of resistance \( R \) and an inductor having reactance \( X_L \). If voltage leads the current by an angle \( 60^\circ \), then

1. \( X_L = R \)
2. \( X_L = 2R \)
3. \( X_L = \sqrt{3}R \)
4. \( X_L = \sqrt{2}R \)
View Answer

In an inductive-resistive (RL) series circuit, the phase angle \( \phi \) is given by \( \tan \phi = \frac{X_L}{R} \). Since \( \phi = 60^\circ \), \( \tan 60^\circ = \frac{X_L}{R} \implies X_L = \sqrt{3}R \).

Question 25: easy

A series LCR circuit contains a capacitor of capacitance \(10^{-6}\text{ F}\) and an inductor of inductance \(10^{-4}\text{ H}\). The resonant frequency of the circuit will be

1. \(10^5\text{ Hz}\)
2. \(10\text{ Hz}\)
3. \(\frac{10^5}{2\pi}\text{ Hz}\)
4. \(\frac{10}{2\pi}\text{ Hz}\)
View Answer

The resonant frequency of a series LCR circuit is given by \(f_0 = \frac{1}{2\pi\sqrt{LC}}\). Substituting values: \(f_0 = \frac{1}{2\pi\sqrt{10^{-4} \times 10^{-6}}} = \frac{10^5}{2\pi}\text{ Hz}\).

Question 26: easy

Assertion (A): If an iron rod is inserted into a steady current carrying solenoid, the current in solenoid decreases.


Reason (R): Magnetic flux linked with solenoid increases.


 

1. (1) Both (A) & (R) are true and the (R) is the correct explanation of the (A)
2. (2) Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
3. (3) (A) is true but (R) is false
4. (4) Both (A) and (R) are false
View Answer

Inserting an iron rod increases magnetic flux \( \Phi \). By Lenz's law, this induces an opposing \( \text{EMF} \), causing current \( \text{I} \) to decrease during insertion.

Question 27: easy

Assertion (A): ac current flows through a bulb and a solenoid connected in series. If a soft iron core is inserted in the solenoid, the bulb glows much brighter.


Reason (R): The inductance of solenoid decreases on inserting soft iron core in it.


 

1. Both A & R are true and the (R) is the correct explanation of the (A)
2. Both A & R are true but the (R) is not the correct explanation of the (A)
3. (A) is true but (R) is false
4. Both (A) and (R) are false
View Answer

Inserting a soft iron core increases solenoid inductance \(L\), thus increasing inductive reactance \(X_L = omega L\). This increases circuit impedance \(Z\), reducing current \(I = V/Z\) and making the bulb dimmer. Both Assertion (A) and Reason (R) are false.

Question 28: easy

Assertion (A): A choke coil has the characteristic of high inductance and low resistance.


Reason (R): More is the inductive property of the choke coil, Power factor of the circuit approaches maximum.


 

1. Both A & R are true and the (R) is the correct explanation of the (A)
2. Both A & R are true but the (R) is not the correct explanation of the (A)
3. (A) is true but (R) is false
4. Both (A) and (R) are false
View Answer

A choke coil has high inductance and low resistance (A is true). Power factor is \(cos\phi = R/Z = R/sqrt{R^2 + X_L^2}\). Higher inductive property (large \(X_L\)) makes \(cos\phi\) approach minimum (0), not maximum. So R is false.

Question 29: easy

Assertion (A): In a series \(LCR\) circuit at resonance, the voltage across the capacitor or inductor may be more than the applied voltage.


Reason (R): At resonance in a series \(LCR\) circuit, the voltages across inductor and capacitor are out of phase.


 

1. Both (A) & (R) are true and the (R) is the correct explanation of the (A)
2. Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
3. (A) is true but (R) is false
4. Both (A) and (R) are false
View Answer

At resonance, \(V_L = V_C\) but they are \(180^\circ\) out of phase. The applied voltage is \(V = IR\). Due to voltage magnification (high \(Q\) factor), \(V_L\) or \(V_C\) can be much greater than \(V\). Reason is true, but it doesn't explain *why* they can be larger than applied voltage, it explains why they cancel out to make \(V=IR\).

Question 30: easy

Assertion (A): Average power consumed in an \(AC\) circuit is equal to average power consumed by resistors in the circuit.


Reason (R): Average power consumed by capacitor and inductor is zero.


 

1. Both (A) & (R) are true and the (R) is the correct explanation of the (A)
2. Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
3. (A) is true but (R) is false
4. Both (A) and (R) are false
View Answer

Average power in \(AC\) is \(P_{avg} = V_{rms} I_{rms} \cos\phi\). For pure inductor or capacitor, \(\phi = \pm \pi/2\) so \(cos\phi = 0\). Only resistors dissipate average power, \(P_{avg} = I_{rms}^2 R\). Hence, R correctly explains A.