Peak Voltage of AC Source – Rankers Physics
Topic: Alternating Current
Subtopic: Average Current and RMS Current

Peak Voltage of AC Source

The peak voltage of the AC source is equal to
The value of voltage applied to the circuit
The rms value of the source
\(\sqrt{2}\) times the rms value of the AC source
\(\frac{1}{\sqrt{2}}\) times the average value of the AC source

Solution:

For a sinusoidal AC voltage source, the relation between peak voltage \(V_0\) and root-mean-square voltage \(V_{\text{rms}}\) is \(V_0 = \sqrt{2}V_{\text{rms}}\).

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