Two unequal soap bubbles are formed one on each side of a tube closed in the middle by a tap. What happens when the tap is opened to put the two bubbles in communication ?
The radii of the two columns in U tube are r1 and r2 (r1 > r2). When a liquid of density \[\rho\] (angle of contact is 0º) is filled in it, the level difference of liquid in two arms is h. The surface tension of liquid is (g = acceleration due to gravity):
If force of cohesion of liquid is three times the force of adhesion between liquid and glass tube molecules, then the shape of meniscus of liquid in this glass tube is:
Two objects A & B of equal density and radius rA = 1 mm and rB = 2 mm are moving in same medium then find the ratio of their terminal velocity \( \frac{v_{B}}{v_{A}}\) in the medium.
The terminal velocity v of a spherical object moving through a viscous medium is directly proportional to the square of its radius, expressed as v
\(r^2 \), when the density and the medium remain constant.
\( \frac{v_B}{v_A} = \left(\frac{r_B}{r_A}\right)^2 = \left(\frac{2}{1}\right)^2 = 4 \)
Thus, the required ratio \( \frac{v_B}{v_A} \) is 4 (Option 3).