Fluid Statics - NEET Physics Questions
Question 1: moderate

The density of the atmosphere at sea level is 1.3 kg/m3. Assume it does not change with altitude and g = 10 ms–2, how high would the atmosphere extend ?

1. 8 km
2. 10 km
3. 12 km
4. 16 km
View Answer
Question 2: moderate

A tube 1 cm2 in cross-section is attached to the top of a vessel 1 cm high and of cross-section 100 cm2. Water is poured into the system filling it to a depth of 100 cm above the bottom of the vessel as shown in figure. Take g = 10 ms–2. Now,

1. Force exerted by the water against the bottom of the vessel is 100 N.
2. Weight of water in the system is 1.99 N.
3. Both (1) and (2) are correct.
4. Neither (1) nor (2) is correct.
View Answer
Question 3:

A ball floats on the surface of water in a container exposed to the atmosphere. When the container is covered and the air is partially removed, then the ball : [Consider buoyancy effect of air also]

1. Rises
2. Gets immersed more in water
3. Remains immersed at its former depth
4. May rise or sink
View Answer
Question 4: moderate

A body with a volume V neither sinks nor floats in a liquid. If the vessel containing the liquid falls with an acceleration g/3 , then the volume of the solid inside the liquid in the falling condition is:

1. V
2. V/2
3. V/3
4. V/6
View Answer
Question 5: difficult

A cylindrical piece of cork of density \[\rho\] of base area A and height h floats in a liquid of density \[\rho\acute{}\]. The cork is slightly depressed and then released. The time period of oscillation of the cork is :

1. \[\pi\sqrt{\frac{g\rho\acute{}}{g\rho}}\]
2. \[\pi\sqrt{\frac{h\rho}{g\rho\acute{}}}\]
3. \[2\pi\sqrt{\frac{h\rho\acute{}}{g\rho}}\]
4. \[2\pi\sqrt{\frac{h\rho}{g\rho\acute{}}}\]
View Answer
Question 6: easy

A cubical box of wood of side 30 cm weighing 21.6 kg floats on water with two faces horizontal. Calculate the depth of immersion of wood.

1. 30 cm
2. 24 cm
3. 20 cm
4. 15 cm
View Answer
Question 7: moderate

A sample of metal weights 210 gram in air, 180 gram in water and 120 gram in an unknown liquid. Then:

1. the density of metal is 3 g/cm3
2. the density of metal is 7 g/cm3
3. density of metal is 4 times the density of the unknown liquid
4. the metal will float in water
View Answer
Question 8: difficult

Two non-mixing liquids of densities \[\rho\] and \[n\rho(n>1)\] are put in a container. The height of each liquid is h. A solid cylinder of length L and density d is put in this container. The cylinder floats with its axis vertical and length pL(p < 1) in the denser liquid. The density d is equal to :

1. \[\left\{ {1+(n+1)p} \right\}\rho\]
2. \[\left\{ {2+(n+1)p} \right\}\rho\]
3. \[\left\{ {2+(n-1)p} \right\}\rho\]
4. \[\left\{ {1+(n-1)p} \right\}\rho\]
View Answer
Question 9: difficult

A tank contains water on top of mercury as shown in figure. A cubical block of side 10 cm is in equilibrium inside the tank. The depth of the block inside mercury is (RD of the material of block = 8.56, RD of mercury = 13.6)

1. 6 cm
2. 5 cm
3. 7 cm
4. 8 cm
View Answer
Question 10: moderate

The reading of spring balance when a block is suspended from it in air, is 60 N. This reading is changed to 40 N when the block is immersed in water. The specific gravity of the block is :

1. 3
2. 2
3. 6
4. 3/2
View Answer

Solution:

  • Loss of weight in water = $$\text{Weight in air} - \text{Weight in water} = 60\text{ N} - 40\text{ N} = 20\text{ N}$$

  • Specific gravity = $$\frac{\text{Weight in air}}{\text{Loss of weight in water}} = \frac{60}{20} = 3$$

Therefore, the specific gravity of the block is 3 (Option 1).