Question 61:
easy
By what percentage will the acceleration due to gravity at a height of 1600 km from the surface of the Earth differ from that on the surface of the Earth? (Take radius of Earth to be 6400 km)
Acceleration due to gravity at height \(h\) is \(g' = g\left(\frac{R}{R+h}\right)^2 = g\left(\frac{6400}{8000}\right)^2 = 0.64g\). The percentage difference is \(\frac{g - 0.64g}{g}\times 100% = 36%\).