Question 221:
easy
A system of two charges \(q_A = 2.5 \times 10^{-7}\text{ C}\) and \(q_B = -2.5 \times 10^{-7}\text{ C}\) are located at points A: \((0, 0, -15\text{ cm})\) and B: \((0, 0, 15\text{ cm})\) respectively. The electric dipole moment of the system is
Electric dipole moment is given by \(p = q \times 2a\), where \(2a\) is the distance between the charges. Here, \(2a = 30\text{ cm} = 0.3\text{ m}\). Thus, \(p = 2.5 \times 10^{-7}\text{ C} \times 0.3\text{ m} = 7.5 \times 10^{-8}\text{ C m}\).