Parallel Plate Capacitor: Practice Problem & Solution
\(N\) identical capacitors are joined in parallel and the combination is charged to a potential \(V\). Now if they are separated and then joined in series then energy of combination will :
Solution Explained:
To solve this problem, we apply the core principles of Parallel Plate Capacitor. Understanding the underlying formula is key to arriving at the correct answer below:
When connected in series, the charges do not change, so the total energy stored remains the same: \(U = N \times \left(\frac{1}{2} C V^2\right)\). However, the individual potential differences add up, so the total potential difference becomes \(NV\).
Leave a Reply