Capacitor Energy Storage and Supply – Rankers Physics

Parallel Plate Capacitor: Practice Problem & Solution

A capacitor of capacitance C is connected across a battery of potential difference V. Assertion (A): The energy stored in capacitor is \( \frac{1}{2} CV^2 \). Reason (R): The energy supplied by the battery is \( CV^2 \).  
Both (A) & (R) are true and the (R) is the correct explanation of the (A)
Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
(A) is true but (R) is false
Both (A) and (R) are false

Short Solution (Best for NEET):

To solve this problem, we apply the core principles of Parallel Plate Capacitor. Understanding the underlying formula is key to arriving at the correct answer below:

Assertion (A) is true: energy stored in a capacitor is \( U = \frac{1}{2} CV^2 \). Reason (R) is true: the total work done by the battery (energy supplied) is \( W = CV^2 \). However, (R) is not the correct explanation for (A), as half of the supplied energy is dissipated as heat.

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