Waves and its Characteristics: Practice Problem & Solution
A wave travelling in positive $x$-direction with $A = 0.2 \text{ m}$ velocity $= 360 \text{ m/s}$ and $\lambda = 60 \text{ m}$, then correct expression for the wave is: (2002)
Solution Explained:
To solve this problem, we apply the core principles of Waves and its Characteristics. Understanding the underlying formula is key to arriving at the correct answer below:
Frequency $n = \frac{v}{\lambda} = \frac{360}{60} = 6 \text{ Hz}$. Equation for wave in positive x-direction is $y = A \sin[2\pi(nt - \frac{x}{\lambda})] = 0.2 \sin[2\pi(6t - \frac{x}{60})]$.
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