Rankers Physics

Waves and its Characteristics: Practice Problem & Solution

A transverse wave propagating along x-axis is represented by $y(x,t) = 8.0\sin(0.5\pi x - 4\pi t - \pi/4)$ where $x$ is in metres and $t$ is in seconds. The speed of the wave is: (2006)
$8\text{ m/s}$
$4\pi\text{ m/s}$
$0.5\pi\text{ m/s}$
$\pi/4\text{ m/s}$

Solution Explained:

To solve this problem, we apply the core principles of Waves and its Characteristics. Understanding the underlying formula is key to arriving at the correct answer below:

From the given wave equation $y = A\sin(kx - \omega t - \phi)$, we identify $k = 0.5\pi\text{ m}^{-1}$ and $\omega = 4\pi\text{ rad/s}$. The wave speed is given by $v = \omega/k = 4\pi / 0.5\pi = 8\text{ m/s}$.

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