Diffraction: Practice Problem & Solution
A screen is placed \(50\text{ cm}\) from a single slit, which is illuminated with \(6000\text{ A^0}\) light. If distance between the first and third minima in the diffraction pattern is \(3\text{ mm}\), the width of the slit is
Solution Explained:
To solve this problem, we apply the core principles of Diffraction. Understanding the underlying formula is key to arriving at the correct answer below:
The distance between the first and third minima on the same side of central maximum is \(\Delta y = \frac{2\lambda D}{d}\). Substituting the values: \(3 \times 10^{-3}\text{ m} = \frac{2 \times 6000 \times 10^{-10}\text{ m} \times 0.5\text{ m}}{d}\), we get \(d = 2 \times 10^{-4}\text{ m} = 0.2\text{ mm}\).
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