Rankers Physics

Young's Double Slit Experiment: Practice Problem & Solution

Two periodic waves of intensities $I_1$ and $I_2$ pass through a region at the same time in the same direction. The sum of the maximum and minimum intensities is: (2008)
$2(I_1 + I_2)$
$I_1 + I_2$
$(\sqrt{I_1} + \sqrt{I_2})^2$
$(\sqrt{I_1} - \sqrt{I_2})^2$

Short Solution (Best for NEET):

To solve this problem, we apply the core principles of Young's Double Slit Experiment. Understanding the underlying formula is key to arriving at the correct answer below:

The maximum intensity is $I_{max} = I_1 + I_2 + 2\sqrt{I_1 I_2}$ and the minimum intensity is $I_{min} = I_1 + I_2 - 2\sqrt{I_1 I_2}$. Their sum is $I_{max} + I_{min} = 2(I_1 + I_2)$.

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