Young's Double Slit Experiment: Practice Problem & Solution
Assertion (A): If width of one of the slit in YDSE is slightly increased, then maximum and minimum both Intensity will increase. Reason (R): Intensity reaching from that slit on screen will slightly increase.
Short Solution (Best for NEET):
To solve this problem, we apply the core principles of Young's Double Slit Experiment. Understanding the underlying formula is key to arriving at the correct answer below:
In YDSE, the intensity of light from a slit is proportional to its width \(I \propto w\). Also, amplitude \(A \propto \sqrt{I}\). If one slit's width increases, its amplitude \(A\) increases. The maximum intensity is \(I_{max} = (A_1+A_2)^2\) and minimum intensity is \(I_{min} = (A_1-A_2)^2\). If \(A_1\) increases, both \(I_{max}\) and \(I_{min}\) will increase. Both A and R are true, and R explains A.
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