Linear Velocity in Circular Motion – Rankers Physics

Uncategorized: Practice Problem & Solution

A body is whirled in a horizontal circle of radius \( 20 text{ cm} \) with an angular velocity of \( 10 text{ rad/s} \). What is its linear velocity at any point on its circular path? (1996)
\( 20 text{ m/s} \)
\( sqrt{2} text{ m/s} \)
\( 10 text{ m/s} \)
\( 2 text{ m/s} \)

Solution Explained:

To solve this problem, we apply the core principles of Uncategorized. Understanding the underlying formula is key to arriving at the correct answer below:

Given: Radius \( r = 20 text{ cm} = 0.20 text{ m} \). Angular velocity \( omega = 10 text{ rad/s} \). The relationship between linear velocity \( v \) and angular velocity \( omega \) is \( v = romega \). Substituting the values, \( v = (0.20 text{ m}) times (10 text{ rad/s}) = 2 text{ m/s} \).

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