Rankers Physics

Uncategorized: Practice Problem & Solution

19. The ratio of the radii of the nuclei $ _{13}Al^{27} $ and $ _{52}Te^{125} $ approximately (1990)
$ 6 : 10 $
$ 13 : 52 $
$ 40 : 177 $
$ 14 : 73 $

Solution Explained:

To solve this problem, we apply the core principles of Uncategorized. Understanding the underlying formula is key to arriving at the correct answer below:

The radius of a nucleus is given by $ R = R_0 A^{1/3} $. The ratio of their radii is $ R_{Al} / R_{Te} = (A_{Al} / A_{Te})^{1/3} = (27 / 125)^{1/3} = 3 / 5 = 6 / 10 $.

Leave a Reply

Your email address will not be published. Required fields are marked *

Similar Practice Questions

Explore conceptually related problems to test your knowledge.

1. A body is executing simple harmonic motion. When the displacements from the mean position is $4 \text{ cm}$ and $5 \text{ cm}$ the corresponding velocities of the body is $10 \text{ cm/sec}$ and $8 \text{ cm/sec}$. Then the time period of the body is: (1991)
2. 10. A circular disc of radius $0.2 meter$ is placed in a uniform magnetic field of induction $\frac{1}{\pi} (\frac{wb}{m^2})$ in such a way that its axis makes an angle of $60^\circ$ with the magnetic field. The magnetic flux linked with the disc is: (2008)
3. 49. Standing waves are produced in $10 \text{ m}$ long stretched string. If the string vibrates in 5 segments and wave velocity is $20 \text{ m/s}$, the frequency is: (1997)
4. 57. The half life of a radio nuclide is 77 days then its decay constant is: (1999)
5. In thermodynamic processes which of the following statements is not true? (2009)