Uncategorized: Practice Problem & Solution
A force of \(6text{ N}\) acts on a body at rest and of mass \(1text{ kg}\). During this time, the body attains a velocity of \(30text{ m/s}\). The time for which the force acts on the body is: (1997)
Solution Explained:
To solve this problem, we apply the core principles of Uncategorized. Understanding the underlying formula is key to arriving at the correct answer below:
Using Newton's second law, acceleration \(a = F/m = 6text{ N} / 1text{ kg} = 6text{ m/s}^2\). Since the body starts from rest (\(u=0\)) and attains a final velocity \(v=30text{ m/s}\), we use \(v = u + at\). So, \(30 = 0 + 6t\), which gives \(t = 30/6 = 5text{ s}\).
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