Rankers Physics

Uncategorized: Practice Problem & Solution

Displacement between max. P.E. position and max. K.E. position for a particle excuting simple harmonic motion is: (2002)
${\pm} \frac{a}{2}$
$+ a$
${\pm} a$
$- 1$

Solution Explained:

To solve this problem, we apply the core principles of Uncategorized. Understanding the underlying formula is key to arriving at the correct answer below:

Max P.E. is at extreme positions (${\pm} a$) and max K.E. is at the mean position ($0$). Hence the displacement between them is ${\pm} a$.

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