Electric Potential: Practice Problem & Solution

Solution Explained:

To solve this problem, we apply the core principles of Electric Potential. Understanding the underlying formula is key to arriving at the correct answer below:

Potential on the surface of a charged conducting sphere is $V = \frac{kQ}{R}$. For equal charges, $V \propto \frac{1}{R}$. Since $R_2 < R_1$, the potential is more on the smaller sphere.