Simple pendulum on moon – Rankers Physics

Equation of SHM: Practice Problem & Solution

Assertion (A): When a simple pendulum is made to oscillate on the surface of moon, its time period increases. Reason (R): Gravity at moon is less than gravity at earth.  
Both (A) & (R) are true and the (R) is the correct explanation of the (A)
Both (A) & (R) are true but the (R) is not the correct explanation of the (A)
(A) is true but (R) is false
Both (A) and (R) are false

Short Solution (Best for NEET):

To solve this problem, we apply the core principles of Equation of SHM. Understanding the underlying formula is key to arriving at the correct answer below:

Assertion (A) is true: The period of a simple pendulum is inversely proportional to the square root of 'g' (\(T = 2pi sqrt{l/g}\)). Reason (R) is true: Gravity on the moon is significantly less than on Earth. Since 'g' decreases, the period 'T' increases, making (R) the correct explanation for (A).

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