Angular SHM and Simple Pendulum: Practice Problem & Solution
Frequency of simple pendulum in a free falling lift is: (1999)
Solution Explained:
To solve this problem, we apply the core principles of Angular SHM and Simple Pendulum. Understanding the underlying formula is key to arriving at the correct answer below:
In a free-falling lift, the effective acceleration due to gravity is zero ($ g_{eff} = g - g = 0 $). Since frequency $ f = \frac{1}{2\pi}\sqrt{\frac{g_{eff}}{l}} $, the frequency becomes zero.
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