Angular SHM and Simple Pendulum: Practice Problem & Solution

Solution Explained:

To solve this problem, we apply the core principles of Angular SHM and Simple Pendulum. Understanding the underlying formula is key to arriving at the correct answer below:

Time period $ T \propto l^{1/2} $. For small percentage changes, $ \frac{\Delta T}{T} \times 100 = \frac{1}{2} \left( \frac{\Delta l}{l} \times 100 \right) $. Thus, the time period increases by $ \frac{1}{2} \times 2\% = 1\% $.