Find the position of the first minimum with respect to central maxima for a single slit of width
0.04 mm , on a screen 2 meters distance , when light from a He -Ne laser λ = 632.8 nm is shone
on the slit.

Two beams of light having intensities I and 4I interfere to produce a fringe pattern on the screen. Phase difference between the beams is π/2 at point A and π at point B. Then the difference between resultant intensities at A and B is

Waves from two slits are in phase at the slits and travel to a distant screen to produce the second minimum of the interference pattern. The difference in the distance travelled by the waves is :

In YDSE setup, light of wavelength 640 nm is used with d = 0.8 m m and D = 1m . If intensity
at central maxima is I0 and it’s position is y = 0,

Minimum thickness of a mica sheet (which should be placed in front of one of the slits in YDSE) required to reduce the intensity at the centre of screen to half of maximum intensity is (the refractive index of the sheet is 3/2) Assume that the sheet does not absorb any light.

In a standard Young’s double slit setup, we get 60 fringes on a section of screen with
monochromatic light of wavelength 4000 Å. If we use monochromatic light of wavelength 6000Å, then the number of fringes that would be obtained in the same section is

In a Young’s double slit experiment, a small detector measures an intensity of illumination of
I units at the centre of the fringe pattern. If one of the two (identical) slits is now covered, the
measured intensity will be

Young’s double slit experiment is carried out by using green, red and blue light, one color at a time .The fringe widths recorded are \[\beta_{G}, \beta_{R} and \beta_{B},\] respectively. Then,

Four harmonic waves of equal frequencies and equal intensities I0 have phase angles 0, π/3, 2π/3 and π . When they are superposed, the intensity of the resulting wave is nI0. The value of n is

In Young’s double slit experiment, one of the slit is wider than other, so that the amplitude of the light from one slit is double of that from other slit. If Im be the maximum intensity, the resultant intensity I when they interfere at phase difference Φ is given by :