Four harmonic waves of equal frequencies and equal intensities I0 have phase angles 0, π/3, 2π/3 and π . When they are superposed, the intensity of the resulting wave is nI0. The value of n is

In Young’s double slit experiment, one of the slit is wider than other, so that the amplitude of the light from one slit is double of that from other slit. If Im be the maximum intensity, the resultant intensity I when they interfere at phase difference Φ is given by :

In the Young’s double slit experiment, the ratio of intensities of bright and dark fringes is 9. This means that :-
(A) The intensities of individual sources are 5 and 4 units respectively
(B) The intensities of individual sources are 4 and 1 units respectively
(C) The ratio of their amplitudes is 3
(D) The ratio of their amplitudes is 2

In a Young’s double slit experiment, the fringe width is found to be 0.4 mm. If the whole apparatus is immersed in water of refractive index 4/3 without disturbing the geometrical arrangement, the new fringe width will be :

In a Young’s double slit experiment the intensity at a point where the path difference is λ/6 (λ being the wavelength of the light used) is I. If I0 denotes the maximum intensity, I/I0 is equal to :

In the Young’s double slit experiment, for which colour the fringe width is least :

The ratio of intensities of consecutive maxima in the diffraction pattern due to a single slit is :

A plane wavefront \[\left( \lambda=6\times 10^{-7}m \right)\] falls on a slit 0.4 mm wide. A convex lens of focal length 0.8m placed behind the slit focusses the light on a screen. What is the linear diameter of second maximum :

For what distance is ray optics a good approximation when the aperture is 4 mm wide and the wavelength is 500 nm :

A light wave is incident normally over a slit of width \[24\times 10^{-5} cm\]. The angular position of second dark fringe from the central maxima is 30 degree. What is the wavelength of light :