Spring Block System - NEET Physics Questions
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Spring Block System

Question 1: difficult

The mass M shown in the figure oscillates in simple harmonic motion with amplitude A. The amplitude of the point P is :

1. k1A/k2
2. k2A/k1
3. k1A/k1+k2
4. k2A/k1+k2
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Question 2: difficult

A block P of mass m is placed on a frictionless horizontal surface. Another block Q of same mass is kept on P and connected to the wall with the help of a spring of spring constant k as shown in the figure. μs is the coefficient of friction between P and Q. The blocks move together performing simple harmonic motion with amplitude A. The
maximum value of the friction force between P and Q is :

1. kA
2. kA/2
3. zero
4. μs mg
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Question 3: difficult

What is the angular frequency of the system shown in the figure?

1. \[ \sqrt[]{\frac{k}{m}} \]
2. \[ \sqrt[]{\frac{k}{2m}} \]
3. \[ \sqrt[]{\frac{k}{3m}} \]
4. \[ \sqrt[]{\frac{2k}{m}}\]
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The system shown consists of two masses \( M \) connected by a spring with a spring constant \( k \). Since the masses are identical, the angular frequency \( \omega \) of the system for oscillations is given by:

\[
\omega = \sqrt{\frac{k}{\text{reduced mass}}}
\]

In this case, the reduced mass \( \mu \) of the system is given by:

\[
\mu = \frac{M \cdot M}{M + M} = \frac{M}{2}
\]

Thus, the angular frequency \( \omega \) is:

\[
\omega = \sqrt{\frac{k}{M/2}} = \sqrt{\frac{2k}{M}}
\]

Answer:

\[
\omega = \sqrt{\frac{2k}{M}}
\]