Question 1:
moderate
Match the following and choose the correct option from given codes :
Question 2:
moderate
The r.m.s. value of potential difference V shown in the figure is :-
Question 3:
moderate
A square wave current switching rapidly between \(+0.5\) ampere and \(-0.5\) ampere is passed through an A.C ammeter. Then the reading shown by it, is
An AC ammeter measures the RMS value of the current. For a symmetric square wave of amplitude \(I_0\), the RMS value is equal to its peak value, \(I_{rms} = I_0 = 0.5\text{ A}\).
Question 4:
moderate
An ac current flowing in a circuit is given by \(i = i_0 sin \omega t\). The minimum time taken to reach zero to rms value of current is
The RMS value is \(i = \frac{i_0}{\sqrt{2}}\). Thus, \(\frac{i_0}{\sqrt{2}} = i_0 sin \omega t ⇒ \omega t = \frac{\pi}{4} ⇒ t = \frac{\pi}{4\omega}\).
Question 5:
moderate
An a.c. voltage given by relation, \(V = 300\sin(100t)\text{ volt}\) is connected with resistor having resistance \(60\ \Omega\) and inductor of inductance \(L\). If peak current in the circuit is \(3\text{ A}\), the value of \(L\) will be (where \(t\) denotes the time in s)
Peak voltage \(V_0 = 300\text{ V}\), peak current \(I_0 = 3\text{ A}\), so impedance \(Z = V_0/I_0 = 100\ \Omega\). Using \(Z = \sqrt{R^2 + (\omega L)^2}\), we have \(100 = \sqrt{60^2 + (100L)^2}\), which gives \(100L = 80 \implies L = 0.8\text{ H}\).