Work Energy and Power - NEET Physics Chapterwise MCQs & PYQs
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NEET Work Energy and Power MCQs & PYQs
Practice NEET Work Energy and Power Questions
Question 1:
easy
Assertion (A): The work done during a round trip is always zero.
Reason (R): No force is required to move a body in its round trip.
Work done by conservative forces in a closed loop is zero. For all forces, it depends on energy change and non-conservative forces. Force is required to move a body, especially to overcome inertia or friction. Therefore, both Assertion (A) and Reason (R) are false.
Assertion (A): Work done by conservative force along closed path is zero.
Reason (R): When an object is moved along closed path beginning and ending are at same point its displacement is zero.
Assertion is true by definition of a conservative force, which does zero work over any closed path.
Reason is also true as displacement is zero for a closed path, i.e., \(\Delta \vec{r} = 0\). However, the reason is not the correct explanation for why work by a conservative force is zero; this is due to path independence and \(\Delta U = 0\) for a closed path.
Thus, both are true, but R is not the correct explanation of A.
Assertion (A): When a non-conservative force is involved in a system, it may dissipate energy.
Reason (R): The work done by a non-conservative force is always negative.
Assertion is true: Non-conservative forces like friction or air resistance dissipate mechanical energy into other forms (e.g., heat).
Reason is false: The work done by a non-conservative force is not always negative. For example, an applied external force can be non-conservative and do positive work on a system.
Assertion (A): The sum of potential and kinetic energy for a system of moving objects is conserved only when no net external force acts on the objects
Reason (R): If no nonconservative force acts on a system of objects, the work done by external forces on a system of objects is equal to change in potential energy plus change in kinetic energy of the system.
Assertion is false: Mechanical energy \(E = K + U\) is conserved when only conservative forces do work. External conservative forces (e.g., gravity) can act and do work, yet mechanical energy can be conserved.
Reason is false: If no non-conservative forces act, then \(\Delta K + \Delta U = 0\), meaning mechanical energy is conserved. In this scenario, the work done by external forces \(W_{ext}\) is not necessarily zero. For instance, gravity does work when an object falls, but \(E\) is conserved.
Assertion (A): An athlete accelerates from rest to its maximum speed due to friction between his shoes and track.
Reason (R): Positive work done by frictional force increases the kinetic energy of athlete.
Assertion is true: An athlete pushes backward on the ground, and the ground exerts a forward static friction force on the athlete, causing acceleration.
Reason is true: The static friction force acts in the direction of the athlete's motion. Therefore, it does positive work, which directly increases the athlete's kinetic energy \(K\) according to the work-energy theorem.
Both A and R are true, and R provides the correct explanation for A.
Assertion (A): Work done by a force is always same in all inertial frame of references.
Reason (R): Work is an invariant physical quantity.
Work done (\(W = \vec{F} \cdot \vec{d}\)) depends on displacement (\(\vec{d}\)) which is frame-dependent in different inertial frames. Therefore, work is not always the same and is not an invariant quantity. Both Assertion and Reason are false.
Assertion (A): Total energy is negative for a bounded system.
Reason (R): Potential energy of a bound system is negative and its magnitude is more than kinetic energy.
For a bound system, the potential energy (\(U\)) is negative and its magnitude is greater than the kinetic energy (\(K\)). Since total energy is \(E = K + U\), \(E\) must be negative. Both Assertion and Reason are true, and Reason correctly explains Assertion.
Assertion (A): Work done is positive when force acts in the direction of displacement.
Reason (R): Work done by frictional force can not be positive.
Work is \(W = \vec{F} \cdot \vec{d} = Fd cos\theta\). If \(theta = 0\), \(W\) is positive, so (A) is true. Frictional force always opposes motion, so work done by it is negative or zero, never positive. So (R) is true. However, (R) does not explain (A).